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3 years ago

Amber is solving the inequality X+61- 12 < 13 by graphing. Which equations should Amber graph?

Mathematics

1 answer:

mafiozo [28]3 years ago

8 0

Answer:

I think No B is the answer

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Help w homework plsssss

Alenkinab [10]

Answer:

Step-by-step explanation:

complementary mean it equals 90 degrees

90-23 = 67

m<2=67

3 0

3 years ago

Mica and Denise are reading the same novel. Mica has read 1/2 of the novel,Denise has read 1/3 of the novel . How much more of t

Diano4ka-milaya [45]

The answer would be 1/6 more.

5 0

3 years ago

Craig left his house at noon and drove 50 miles per hour until 3PM. Then he drove the next 5 hours at 70 miles per hour. Calcula

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

Craig left his house at noon and drove 50 miles per hour until 3PM. Then he drove the next 5 hours at 70 miles per hour. Calculate the average rate of change for the entire trip.

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3 years ago

X²+y²-6x+14y-1=0<br> and please show your work so I can learn

Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

$x^2 + y^2 -6x+14y-1=0$

We need to use the Quadratic Formula*

$x =\frac{-b+\sqrt{b^2}-4ac }{2a}$ , $\frac{-b-\sqrt{b^2} -4ac }{2a}$

Thus, given the problem:

$a = 1, b=-6, c=y^2+14y-1$

So now we just need to plug them in the Quadratic Formula*

$x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$ , $x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$

As you can see, it is a mess right now. Therefore, we need to simplify it

$x=\frac{6+2\sqrt{10-y^2-14y} }{2}$ , $x = \frac{6-2\sqrt{10-y^2-14y} }{2}$

Now that's get us to the final solution:

$x=3+\sqrt{10-y^2-14y}$ , $x=3-\sqrt{10-y^2-14y}$

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0

2 years ago

Please Help me Please Please the question and options are in the picture

Lapatulllka [165]

If you eliminate the parentheses, then add mq, you have

... y - p + mq = mx

Then dividing by m gives you the equation for x:

... x = (y - p + mq)/m

3 0

2 years ago