To represent this scenario, you will look at what is happening mathematically and represent it.
Beginning with 5, this will double each day, so 5 x 2 is the deposit.
Then, this amount will double, so (5 x 2) x 2 is the deposit.
Next this will double, and so on.
What is happening is that it is always doubling the previous day's deposit, so x 2 x 2 x 2, etc... you will use exponents to show the number of days that it doubled.
y = 5 x 2^x
Recall that

Dividing both sides by cosh²(x) gives

Also, recall the identity

Then

30. is 8 [-5] [3] [-2] -2
Answer:
For significance levels lower than 0.07, the null hypothesis would be rejected.
Step-by-step explanation:
Decision regarding the null hypothesis:
The decision depends on the p-value of the test.
If the p-value of the test is less than the significance level, the null hypothesis is reject.
If the p-value of the test is more than the significance level, the null hypothesis is not reject.
The analyst reported a p-value of 0.07. For what significance level of will the null hypothesis would be rejected?
From the theory above, for significance levels lower than 0.07, the null hypothesis would be rejected.