Answer:
-2480
Step-by-step explanation:
31 * -80 =-2480
Not sure how to explain this more, but I hope this helps!
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Answer:
iiiii
Step-by-step explanation:
Answer:
a=-7.68
Step-by-step explanation:
3a+13.61=-9.43
-13.61
_____________
-23.04
3a=-23.04
-23.04/3= -7.68
