The answer to your question is -10
Answer: When dividing by 100, move the decimal two places to the left
Step-by-step explanation: 0.1 / 100 = 0.001
There are 2 zeros in 100 so you move the decimal to the left 2 times when you are dividing. When you move the decimal 2 times in 0.1 you get 0.001
Answer:

Step-by-step explanation:
Use cosine:


We have:

Substitute:

<em>cross multiply</em>
<em>divide both sides by 9063</em>

Answer:
a. 0.12109
b. 0.0001668
c .0.9726
d. 0.01038
e. 0.01211
f. 0.000001731
Step-by-step explanation:
Sample size = 580
Defective units = 8
Number of picks = 2
a) If the first container is defective, there 7 defective containers left in a population of 579. The probability of selecting a defective one is:

b) The probability that both are defective is given by:

c) The probability that both are acceptable is given by:

d) In this case, two defective units were removed from the batch, the probability that the third is also defective is:

e) In this case, one acceptable and one defective unit were removed from the batch, the probability that the third is also defective is:

f) The probability that all three are defective is given by:

Answer:100
Step-by-step explanation: