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4 years ago

The image of point A is A' B' C' D'

Mathematics

2 answers:

pav-90 [236]4 years ago

8 0

Answer: A'

Step-by-step explanation:

From the given figure , it can be seen that the quadrilateral ABCD is translated to produce A'B'C'D' by some distance in a particular direction.

A translation is a kind of rigid motion used in geometry to trace a function that maps an shape a particular distance.
The line segments joining a vertex in the pre-image to the corresponding vertex in the image are congruent and parallel.

We can see that the point A' in the image is corresponding to the point A in the pre-image.

Hence, the image of point A is A' .

11Alexandr11 [23.1K]4 years ago

5 0

Answer:

A' because it is translated to another position.

Hope this helps

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A rectangle has a length of (2m - 5) inches and a width of (4m - 2) inches. If the rectangle has a perimeter of 382 inches, then

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Step-by-step explanation:

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4 years ago

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3 years ago

Jake and his dad are making flags for a scouting project.They are going to make(6,12,18) flags . Each flag takes (2/3,3/4,5/6) o

evablogger [386]

Answer:

The total yards of cloth needed for the flags = 28

Step-by-step explanation:

Given:

Jake and his dad are making (6,12,18) different types of flags.

Each flag takes $(\frac{2}{3},\frac{3}{4},\frac{5}{6})$ of a yard of cloth.

To find the total yards of cloth needed in all.

Solution:

Flag A :

Each flag requires = $\frac{2}{3}$ of a yard of cloth

Total number of this flag = 6

Total cloth required for this flag = $\frac{2}{3}\times 6 = 4\ yd$

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Each flag requires = $\frac{3}{4}$ of a yard of cloth

Total number of this flag = 12

Total cloth required for this flag = $\frac{3}{4}\times 12 = 9\ yd$

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Total number of this flag = 18

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8 0

4 years ago

A researcher has developed a new drug designed to reduce blood pressure. In an experiment, 21 subjects were assigned randomly to

Paladinen [302]

Answer:

Step-by-step explanation:

Hello!

The objective of the research is to compare the newly designed drug to reduce blood pressure with the standard drug to test if the new one is more effective.

Two randomly selected groups of subjects where determined, one took the standard drug (1- Control) and the second one took the new drug (2-New)

1. Control

X₁: Reduction of the blood pressure of a subject that took the standard drug.

n₁= 23

X[bar]= 18.52

S= 7.15

2. New

X₂: Reduction of the blood pressure of a subject that took the newly designed drug.

n₂= 21

X[bar]₂= 23.48

S₂= 8.01

The parameter of study is the difference between the two population means (no order is specified, I'll use New-Standard) μ₂ - μ₁

Assuming both variables have a normal distribution, there are two options to estimate the difference between the two means using a 95% CI.

1) The population variances are unknown and equal:

[(X[bar]₂-X[bar]₁)± $t_{n_1+n_2-2;1-\alpha /2}$ *( $Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$ )]

$t_{n_1+n_2-2;1-\alpha /2}= t_{23+21-2;1-0.025}= t_{42;0.975}= 2.018$

$Sa=\sqrt{\frac{(n_1-1)*S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{22*7.15^2+20*8.01^2}{42} }= 7.57$

[23.48-18.52]±2.018*( $7.57*\sqrt{\frac{1}{21} +\frac{1}{23} }$ )]

[0.349; 9.571]

2) The population variables are unknown and different:

Welche's approximation:

[(X[bar]₂-X[bar]₁)± $t_{Dfw;1-\alpha /2}$ *( $\sqrt{\frac{S_1^2}{n_1} +\frac{S_2^2}{n_2} }$ )]

$Df_{w}= \frac{(\frac{S_1^2}{n_1} +\frac{S^2_2}{n_2} )^2}{\frac{(\frac{S_1^2}{n_1} )^2}{n_1-1}+ \frac{(\frac{S_2^2}{n_2} )^2}{n_2-1} } = \frac{(\frac{7.15^2}{23} +\frac{8.01^2_2}{21} )^2}{\frac{(\frac{7.15^2}{21} )^2}{20}+ \frac{(\frac{8.01^2}{23} )^2}{22} } = 42.85= 42$

$t_{Df_w;1-\alpha /2}= t_{42; 0.975}= 2.018$

[(23.48-18.52)±2.018 $\sqrt{\frac{7.15^2}{23} +\frac{8.01^2}{21} }$ ]

[0.324; 9.596]

I hope this helps!

4 0

3 years ago