Answer:
always
Step-by-step explanation:
A parallelogram is an example of a quadrilateral. So its sides are qual to each other
Answer:
The correct option is;
ΔCED ~ ΔCAB
Step-by-step explanation:
Given that the translation maps angle ∠D to angle ∠B, we have;
Angle ∠D is congruent to ∠B (Given)
Segment ED is parallel to segment AB (lines having similar angles to a common transversal)
Therefore, ∠A is congruent to ∠E, (Angle on the same side of a transversal to two parallel lines)
∠C is congruent to ∠C reflexive property
Therefore, we have;
∠C ≅ ∠C
∠E ≅ ∠A
∠D ≅ ∠B
Which gives ΔCED is similar to ΔCAB (not ΔCBA)
