Answer:
uh you didnt put the picture please put the picture i really want to help you:)
Step-by-step explanation:
Answer: Ellie borrowed $150.
Step-by-step explanation:
I = PRT
39 = P x 0.065 x 4
39 = P x 0.26
Divide both sides by 0.26
150 = P
If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show

Let
. Compute the inverse:
![f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}](https://tex.z-dn.net/?f=f%5Cleft%28f%5E%7B-1%7D%28x%29%5Cright%29%20%3D%20%5Csqrt%7B1%20%2B%20f%5E%7B-1%7D%28x%29%5E3%7D%20%3D%20x%20%5Cimplies%20f%5E%7B-1%7D%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%5E2-1%7D)
and we immediately notice that
.
So, we can write the given integral as

Splitting up terms and replacing
in the first integral, we get

Answer:
The reviewers can determine the experiment's feasibility.
Step-by-step explanation:
First of all this isn't math but the answer is between A & B, typically it is checked for mistakes that could lead to it being flawed. From this It is most likely A due to it being a paper and not an actual experiment, they would be looking for if it COULD happen, not if it WILL happen. They wouldn't add their own findings to someone elses paper, and it typically isn't for funding.