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Nat2105 [25]
3 years ago
15

Write 2x+5/x + 3/x+3 as a single fraction to it's simplest form​

Mathematics
1 answer:
san4es73 [151]3 years ago
8 0

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sana makatulonh

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Which figures can be used to find the area of the composite figure? Choose exactly two answers that are correct. A. a rectangle
Romashka [77]
B and C is the correct answer
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3 years ago
HELP PLEASE!!!! A window is 4 feet wide and 8 feet tall. A rectangle is shown. The length of the rectangle is labeled 4 feet. Th
Bingel [31]
First, always draw. You learned to draw in kindergarben (Yes I spelled it like that on purpose LOL) for a reason.

1) Draw your rectangle on a piece of paper or paint. 
2) Scale factor each side to enlarge which means you're going to multiply. 
--- Note if it said 'to reduce' then you would divide.
3) Then find the area by multiplying the two given sides (12 x 6 = 72).
4) Don't forget your unit of measurement - 72ft²

So your answer is D.

3 0
4 years ago
Read 2 more answers
Jalil and Victoria are each asked to solve the equation ax – c = bx + d for x. Jalil says it is not possible to isolate x becaus
uysha [10]

Answer:

x=\frac{d+c}{a-b}

Step-by-step explanation:

The equation is:

a x - c = b x + d

so we subtract b x from both sides to group the terms that contain x on the left:

a x - b x - c = d

add c to both sides to isolate the terms in x on the left:

a x - b x = d + c

extract "x" as common factor on the left:

x (a - b) = d + c

divide both sides by the quantity (a - b) to isolate the "x":

x = (d + c) / (a - b)

or:    x=\frac{d+c}{a-b}

5 0
3 years ago
You have 800 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in half. What are the larg
katovenus [111]
Problema Solution

You have 800 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in half. What are the largest dimensions of this enclosure that you could build?

Answer provided by our tutors

Make a drawing and denote:


x = half of the length of the enclosure


2x = the length of the enclosure


y = the width of the enclosure


P = 800 ft the perimeter


The perimeter of the two enclosures can be expressed P = 4x + 2y thus


4x + 3y = 800


Solving for y:

........

click here to see all the equation solution steps

........

y = 800/3 - 4x/3


The area of the two enclosure is A = 2xy.


Substituting y = 800/3 - 4x/3 in A = 2xy we get


A = 2x(800/3 - 4x/3)


A =1600x/3 - 8x^2/3


We need to find the x for which the parabolic function A = (- 8/3)x^2 + (1600/3)x has maximum: 


x max = -b/2a, a = (-8/3), b = 1600/3


x max = (-1600/3)/(2*(-8/3))


x max = 100 ft


y = 800/3 - 4*100/3


y = 133.33 ft


2x = 2*100


2x = 200 ft

3 0
3 years ago
Based on the table, what was the rate of change of the balance of the students savings account in dollars and cents per week​
andrew-mc [135]

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4 0
3 years ago
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