Answer:
B.
Step-by-step explanation:
Well we know that
so we can get the 2 outside of the radical
and we can get the x^2 outside too.
and we also can get y outside.
so we have:
![2x^{2}y\sqrt[5]{7xy^3}](https://tex.z-dn.net/?f=2x%5E%7B2%7Dy%5Csqrt%5B5%5D%7B7xy%5E3%7D)
Answer:
Unless im being completely braindead right now there isn't a whole number that works with this. When simplified its 5/2 or 2.5 but because it isn't an actual whole number (like 2, 4 and 6) they don't count.
Answer:
4
Step-by-step explanation:
The square root of 16 is four since 4 x 4 is 16.
Inverse property of multiplication
(a*1/a=1)
