If by P=5ft you mean the radius is 5 then c = 2pi r or c = 10pi or approx 31.4 ft
Answer:
There is only one distinct triangle possible, with m∠N ≈ 33°. i hope this helps :)
Step-by-step explanation:
In △MNO, m = 20, n = 14, and m∠M = 51°. How many distinct triangles can be formed given these measurements?
There are no triangles possible.
There is only one distinct triangle possible, with m∠N ≈ 33°.
There is only one distinct triangle possible, with m∠N ≈ 147°.
There are two distinct triangles possible, with m∠N ≈ 33° or m∠N ≈ 147°.
Ni : Zn: Cu = 7:2:9 =7x : 2x : 9x
7x+2x+9x = 3.8
18x=3.8
x=3.8/18=1.9/9≈0.21
Ni: 7x=7*0.21=1.47 ≈1.5 kg
Zn: 2x=2*0.21=0.42≈0.4 kg
Cu: 9x=9*0.21=1.89 ≈1.9 kg
Check 1.5+0.4+1.9 =3.8 True
There would be 2034 students competing in 2012.
We can write a simple equation to find this answer. Let X, be the number of students starting in 2012. Then, we multiply by 0.9 and 1.1 to get to 2014. To work backwards, just divide by 1.1, then by 0.9.
2014 / 1.1 / 0.9 = 2034
