For this case, we want to know what fraction of the Burns High School girls play volleyball. For this, we make a rule of three based on the female students
![\frac {3} {5} ---------> 1\\\frac {1} {3} ---------> x](https://tex.z-dn.net/?f=%5Cfrac%20%7B3%7D%20%7B5%7D%20---------%3E%201%5C%5C%5Cfrac%20%7B1%7D%20%7B3%7D%20---------%3E%20x)
Where "x" represents the fraction of women who play volleyball
![x = \frac {\frac {1} {3} * 1} {\frac {3} {5}}\\x = \frac {5} {9}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%20%7B%5Cfrac%20%7B1%7D%20%7B3%7D%20%2A%201%7D%20%7B%5Cfrac%20%7B3%7D%20%7B5%7D%7D%5C%5Cx%20%3D%20%5Cfrac%20%7B5%7D%20%7B9%7D)
Thus,
are women who play volleyball.
Answer:
![\frac {5} {9}](https://tex.z-dn.net/?f=%5Cfrac%20%7B5%7D%20%7B9%7D)
Solve the formula for h, so you need to isolate/get h by itself in the equation:
A = 1/2bh Multiply the inverse of 1/2, which is 2/1 or 2 on both sides to get rid of the 1/2
![(\frac{2}{1})A=(\frac{2}{1})\frac{1}{2}bh](https://tex.z-dn.net/?f=%28%5Cfrac%7B2%7D%7B1%7D%29A%3D%28%5Cfrac%7B2%7D%7B1%7D%29%5Cfrac%7B1%7D%7B2%7Dbh)
2A = bh Now divide by b on both sides
![\frac{2A}{b} =\frac{bh}{b}](https://tex.z-dn.net/?f=%5Cfrac%7B2A%7D%7Bb%7D%20%3D%5Cfrac%7Bbh%7D%7Bb%7D)
Your answer is C
<em>A) 21</em>
- <em>Step-by-step explanation:</em>
<em>Hi there ! </em>
<em>
</em>
<em>multiples of 7 = all form numbers n×7 ; n ∈ N</em>
<em>21 = 3×7</em>
<em>29 = prime number</em>
<em>27 = 3³</em>
<em>23 = prime number</em>
<em>
</em>
<em><u>the only multiple of 7 is </u></em><em><u>21</u></em>
<em />
<em>Good luck !</em>
Answer:
137
Step-by-step explanation:
Sum of opposite angles in a quadrilateral embedded in a circle = 180
43+x=180
x=180-43
x=137
The answer to your question is
8x + 8