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3 years ago

Simplify the equation

Mathematics

1 answer:

Arturiano [62]3 years ago

7 0

Answer:

$\dfrac{16x^3-37x^2-16x+37}{x^2+2}$

Step-by-step explanation:

There aren't any factors that cancel (except 3x). The best you can do is multiply it out.

$\displaystyle\frac{\frac{3x^2-3}{x}}{\frac{3(x^2+2)}{16x^2-37x}}=\frac{3(x^2-1)}{x}\cdot\frac{16x^2-37x}{3(x^2+2)}\\\\=\frac{x(x^2-1)(16x-37)}{x(x^2+2)}=\frac{16x^3-37x^2-16x+37}{x^2+2}$

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3 years ago

See attachment for the whole question.

KengaRu [80]

Using probability concepts, it is found that:

a) $\frac{4}{13}$ probability of drawing a card below a 6.

b) $\frac{4}{9}$ odds of drawing a card below a 6.

c) We should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.

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A probability is the number of desired outcomes divided by the number of total outcomes.

Item a:

In a standard deck, there are 52 cards.
There are 4 types of cards, each numbered 1 to 13. Thus, $4 \times 5 = 20$ are less than 6.

Then:

$p = \frac{20}{52} = \frac{4}{13}$

$\frac{4}{13}$ probability of drawing a card below a 6.

Item b:

Converting from probability to odd, it is:

$\frac{4}{13 - 4} = \frac{4}{9}$

$\frac{4}{9}$ odds of drawing a card below a 6.

Item c:

The law of large numbers states that with a large number of trials, the percentage of each outcome is close to it's theoretical probability.
Thus, we should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.

A similar problem is given at brainly.com/question/24233657

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Answer:

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Step-by-step explanation:

We know that,

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Step-by-step explanation:

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