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Alex Ar [27]
3 years ago
8

PLEASE HELPPP !!!!! WILL MARK BRAINLIEST TO WHOEVER GETS IT RIGHT

Mathematics
2 answers:
Alika [10]3 years ago
4 0

Answer:

128° because it is same side exterior with <5

Step-by-step explanation:

< 6 =  \:  < 4 =  \:  <  1 = 128 \degree

Jlenok [28]3 years ago
4 0

Answer:

128 because it corresponding with 5

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SOMEONE PLEASE PLEASE HELP ME
slava [35]

Answer:

taking cos

co62=b/h

cos 62=x/12

0.46947x12=x

so, x = 5.633

rounding off

x= 6

6 0
3 years ago
Read 2 more answers
The outside of a picture frame measures 14 in and 20 in 196in^2 of the picture shows find the thickness of the frame
LuckyWell [14K]
The described picture frame can be visualized into two separate parts. The first area is equal to the area using the outermost dimensions for the length and width. 
             Area = Length x Height
              Area = (20 in) x (14 in) 
              Area = 280 in²

We are given that the area is only equal to 192 in². We subtract this value from the computed area.
         Difference = 280 in² - 192 in²
               difference = 88 in²

This area is equal to the area of the hollow space inside the frame. That is equal to,
      height = 20 in - 2x
      length = 14 in - 2x

The area,
               88 = (20 - 2x)(14 - 2x)

Simplify the right hand side of the equation.
             88 = 280 - 68x + 4x²

Divide the equation by 4,
            22 = 70 - 17x + x²

Transposing,
                x² - 17x - 48 = 0
The factors of the equation is 58.2. 

Thus, the thickenss is equal to 58.2 in
5 0
3 years ago
The producer of a certain bottling equipment claims that the variance of all its filled bottles is .027 or less. A sample of 30
o-na [289]

Answer:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

b. between .025 and .05

Step-by-step explanation:

Previous concepts and notation

The chi-square test is used to check if the standard deviation of a population is equal to a specified value. We can conduct the test "two-sided test or a one-sided test".

\bar X represent the sample mean

n = 30 sample size

s= 0.2 represent the sample deviation

\sigma_o =\sqrt{0.027}=0.164 the value that we want to test

p_v represent the p value for the test

t represent the statistic

\alpha= significance level

State the null and alternative hypothesis

On this case we want to check if the population standard deviation is less than 0.027, so the system of hypothesis are:

H0: \sigma \leq 0.027

H1: \sigma >0.027

In order to check the hypothesis we need to calculate the statistic given by the following formula:

t=(n-1) [\frac{s}{\sigma_o}]^2

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

t=(30-1) [\frac{0.2}{0.164}]^2 =42.963

What is the approximate p-value of the test?

The degrees of freedom are given by:

df=n-1= 30-1=29

For this case since we have a right tailed test the p value is given by:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

And the best option would be:

b. between .025 and .05

6 0
3 years ago
What is the value of x? Enter your answer in the box.
yan [13]

Answer:

Did you find the answer?

Step-by-step explanation:


3 0
3 years ago
Can someone give me the answer for this? __ (5 + 4) = 2 * 5 + 2 * 4
wariber [46]

Answer:

the answer is two man..ya know

5 0
3 years ago
Read 2 more answers
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