All categories

3 years ago

Please help and show work if possible. thank you!!

Mathematics

1 answer:

Elena-2011 [213]3 years ago

3 0

10. Horizontal shift of 50, vertical shift of -20, horizontal shift of -50. Think of it on a plane, with right in the positive x-axis and up in the positive y-axis. The cans go right 50ft, then down 20ft, then left 50ft. In terms of the horizontal and vertical, they go 50ft in the positive horizontal axis, then 20ft in the negative vertical axis, then 50ft in the negative horizontal axis. Therefore, the cans have a horizontal shift of 50, then a vertical shift of -20, then a horizontal shift of -50.

11. Since the partition and the wall are parallel, the triangles are similar. This means that the ratio between the sides are the same for the small triangle and the big triangle. The small triangle (made by the partition) is 3m wide and 2m tall. Since the big triangle (made by the wall) is 4m tall, the sides of the big triangle are twice the size of the small triangle. Therefore, the big triangle is 6m wide. We cannot forget to subtract the 3m from the small triangle, since we only want to know how far the partition is from the wall, not how far the point is from the wall.
The wall is 3m away from the partition.

You might be interested in

Find the minimum and maximum of f(x,y,z)=x^2+y^2+z^2 subject to two constraints, x+2y+z=4 and x-y=8.

Alika [10]

The Lagrangian for this function and the given constraints is

$L(x,y,z,\lambda_1,\lambda_2)=x^2+y^2+z^2+\lambda_1(x+2y+z-4)+\lambda_2(x-y-8)$

which has partial derivatives (set equal to 0) satisfying

$\begin{cases}L_x=2x+\lambda_1+\lambda_2=0\\L_y=2y+2\lambda_1-\lambda_2=0\\L_z=2z+\lambda_1=0\\L_{\lambda_1}=x+2y+z-4=0\\L_{\lambda_2}=x-y-8=0\end{cases}$

This is a fairly standard linear system. Solving yields Lagrange multipliers of $\lambda_1=-\dfrac{32}{11}$ and $\lambda_2=-\dfrac{104}{11}$ , and at the same time we find only one critical point at $(x,y,z)=\left(\dfrac{68}{11},-\dfrac{20}{11},\dfrac{16}{11}\right)$ .

Check the Hessian for $f(x,y,z)$ , given by

$\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}$

$\mathbf H$ is positive definite, since $\mathbf v^\top\mathbf{Hv}>0$ for any vector $\mathbf v=\begin{bmatrix}x&y&z\end{bmatrix}^\top$ , which means $f(x,y,z)=x^2+y^2+z^2$ attains a minimum value of $\dfrac{480}{11}$ at $\left(\dfrac{68}{11},-\dfrac{20}{11},\dfrac{16}{11}\right)$ . There is no maximum over the given constraints.

7 0

3 years ago

Find the unknown side or angle as indicated.<br> Round each side length to the nearest tenth

Rainbow [258]

SOLVE THE EQUATIONS

8 0

3 years ago

A girl is 6 years younger than her brother.the product of their ages is 135.find their ages<br>

Vaselesa [24]

Answer:

Brother's age = 15

Sister's age = 9

Step-by-step explanation:

4 0

2 years ago

I need help ASAP! I will give your answer the brainiest answer

Korvikt [17]

This graph will start at (.5, 0) as the vertex.

To find this, all you need to do if find the point where inside the absolute value sign is equal to 0. Since the graph can never have a negative value, this will be the lowest point.

2x - 1 = 0

2x = 1

x = .5

From there, you can plot each point by going up two and to the left one.

Examples of Points: (1.5, 2) and (2.5, 4)

You can also plot the other side of the graph by going up two and to the right one.

These points can be found using the slope, which is the number attached to x (2).

Example of Points (-.5, 2) and (-1.5, 4).

8 0

2 years ago

¿Por qué un conjunto numerable es una función biyectiva?????

WITCHER [35]

En matemáticas, un conjunto contable es un conjunto con la misma cardinalidad (número de elementos) que un subconjunto del conjunto de números naturales. Un conjunto contable es un conjunto finito o un conjunto contable infinito.

8 0

3 years ago