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2 years ago

11

PLZ HELP AND IF U TAKE MY POINTS I WILL REPORT U AN WHO EVER HELPS I WIL GIVE BRAINIEST

1 answer:

Sphinxa [80]2 years ago

6 0

Answer:

the second one I can't give a explanation cause my wrist is broken so it's harder to type hope this helps

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Which pair of slopes represent perpendicular lines?

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If 8 apples can make 3 pies, then how many pies can you make with 24 apples?

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Read 2 more answers

Use any method to multiply (3a + 2b - c)(a - b + 2c).

Alla [95]

Answer: $3a^{2}-ab + 5ac- 2b^{2} + 5bc-2c^{2}$

Step-by-step explanation:

(3a + 2b − c) (a − b + 2c)

Expand (3a + 2b − c) (a − b + 2c) by multiplying each term in the first expression by each term in the second expression.

3a ⋅ a + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3 (a ⋅ a) + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 + 3 ⋅ −1ab + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 3 ⋅ 2ac + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1b ⋅ b + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1 (b ⋅ b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1b^2 + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 2 ⋅ 2bc − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca − 1 ⋅ −1cb − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + 1cb − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2c ⋅ c

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2 (c ⋅ c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2c^2

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 2c^2

3a^2 − 3ab + 2ab + 6ac − 2b^2 + 4bc − ca + cb − 2c^2

3a^2 − ab + 6ac − 2b^2 + 4bc − ca + cb − 2c^2

3a^2 − ab − 2b^2 + 4bc + 6ac − 1ac + cb − 2c^2

3a^2 − ab − 2b^2 + 4bc + 5ac + cb − 2c^2

3a^2 − ab − 2b^2 + 4bc + bc + 5ac − 2c^2

3a^2 − ab − 2b^2 + 5bc + 5ac − 2c^2

3a^2 − ab − 2b^2 + 5ac + 5bc − 2c^2

3a^2 − ab + 5ac − 2b^2 + 5bc − 2c^2

6 0

3 years ago