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3 years ago

PLZ HELP AND IF U TAKE MY POINTS I WILL REPORT U AN WHO EVER HELPS I WIL GIVE BRAINIEST

Mathematics

1 answer:

Sphinxa [80]3 years ago

6 0

Answer:

the second one I can't give a explanation cause my wrist is broken so it's harder to type hope this helps

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What is 3/4*16/21 Simplify fractors

nikklg [1K]

$\bf \cfrac{3}{4}\cdot \cfrac{16}{21}\implies \cfrac{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\cdot \cfrac{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 4}{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 7}\implies \cfrac{4}{7}$

4 0

3 years ago

Solve each equation. Record your work and check your solution. a. 5(x-2)+(-9)= -7(1-x)

Daniel [21]

The solution for equation is x = -6

Solution:

Given equation is:

$5(x-2) + (-9) = -7(1-x)$

We have to solve the equation

According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right

Therefore, solve for brackets in given equation

$5(x-2) + (-9) = -7(1-x)\\\\5x - 10 -9 = -7 + 7x$

Solve for terms in left hand side of equation

$5x - 19 = -7+7x$

Move the variables to one side and constants to other side

$7x -5x = -19+7\\\\2x = -12\\\\Divide\ both\ sides\ by\ 2\\\\x = -6$

Thus the solution for equation is x = -6

8 0

3 years ago

Two and one third minus two thirds

Savatey [412]

The answer to 2 1/3 - 2/3 is 1 2/3

4 0

2 years ago

For s=5 and t=8, 3st²-s²: 3st²-s² =

melomori [17]

Step-by-step explanation:

Given,

s=5

t=8

solution,

= 3st² - s²

= 3*5*8² - 5²

= 3*5*64 - 25

= 960 - 25

= 935

8 0

2 years ago

A = 1/2f(s + z) for s Solve the following formula for the specified variable

Marat540 [252]

Step-by-step explanation:

$\huge{\mathtt{\red{\underbrace{\overbrace{\pink{\boxed{\boxed{\blue{answer}}}}}}}}}$

It is a little unclear when you state the problem what exactly is going on with that fraction. This is a common issue when you try to type up equations. On the right side, you have a fraction bar and then a bunch of stuff after it. We need to clear up what is supposed to be in the numerator and what is supposed to stay in the denominator. This is important not just for typing up questions on the internet to get help but in using your calculator as well. If what the equation means is that both "f" and "q+z" are in the denominator, but then on your calculator you type something 1 / 2 * f * ( q + z ), most calculators (e.g. TI 83/84 and almost any basic or scientific model) will interpret that as meaning only the 2 is on the bottom and the rest is on top.

If you meant the f and the q+z are on top, then Steve's answer is good.

If you meant the f and the q+z are supposed to be on the bottom, then we have a little bit different process.

First, write down the operations that are happening to q, and in what order they happen from inside out, that is, according to the regular PEMDAS rule:

1. z is added

2. 2f is multiplied

3. The result is divided into 1 (as opposed to being divided by 1).

So, to solve for q, we "invert" the order of operations and do the inverse operation of our 3 steps, and also in reverse order.

1. To get the big thing out of the denominator (Step 3), we will multiply both sides by 2f(q+z). Now we have:

C*2f(q+z) = 1, or as we normally write it,

2Cf(q+z) = 1

2. Now we have to adjust our steps just a little bit because we have the *C part too. So we will change Step 2 above to "2Cf is multiplied." We invert that by dividing, so we have:

q+z = 1/[2Cf]. Notice how I put brackets around the entire denominator so it's clear!

3. Finally to invert Step 1 we subtract z:

q = 1/[2Cf] - z

8 0

3 years ago