A is your answer. The box is your IQR of 5-8.5, your median is 7, and your range is 2-10
Answer:
p= 2.5
q= 7
Step-by-step explanation:
The lines should overlap to have infinite solutions, slopes should be same and y-intercepts should be same.
Equations in slope- intercept form:
6x-(2p-3)y-2q-3=0 ⇒ (2p-3)y= 6x -2q-3 ⇒ y= 6/(2p-3)x -(2q+3)/(2p-3)
12x-( 2p-1)y-5q+1=0 ⇒ (2p-1)y= 12x - 5q+1 ⇒ y=12/(2p-1)x - (5q-1)/(2p-1)
Slopes equal:
6/(2p-3)= 12/(2p-1)
6(2p-1)= 12(2p-3)
12p- 6= 24p - 36
12p= 30
p= 30/12
p= 2.5
y-intercepts equal:
(2q+3)/(2p-3)= (5q-1)/(2p-1)
(2q+3)/(2*2.5-3)= (5q-1)/(2*2.5-1)
(2q+3)/2= (5q-1)/4
4(2q+3)= 2(5q-1)
8q+12= 10q- 2
2q= 14
q= 7
Area=(Theta/2) * r^2 This should be it, obviously Theta is your angle and you should use radiants in theory.
Answer:
It should be $378. sorry if I am wrong.
Step-by-step explanation:
Answer:
By the Central Limit Theorem, the average value for all of the sample means is 14.
Step-by-step explanation:
We use the central limit theorem to solve this question.
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, the sample means of size n can be approximated to a normal distribution with mean and standard deviation, which is also called standard error 
If the population mean is μ = 14, then what is the average value for all of the sample means?
By the Central Limit Theorem, the average value for all of the sample means is 14.
