Answer:
mee
Step-by-step explanation:
Answer:
y= -3/2x+9
Step-by-step explanation:
Well we have to know that to find a line perpendicular to a given line, you have to have opposite slopes. So that makes the equation begin as y=-3/2x because it's opposite of y=2/3x. Then we have to make sure it goes through the point (4,3). To do that, I tweaked the numbers in my graphing calculator and it worked with 9! So the equation is y= -3/2x+9
Answer:
It is a polynomial of doom. mwahahahah, you cant stop me spider man
Step-by-step explanation:
Answer:
The 95% confidence interval is

Step-by-step explanation:
From the question we are told that
The first sample size is 
The first sample mean is
The first standard deviation is 
The second sample size is 
The second sample mean is 
The second standard deviation is 
Generally the degree of freedom is mathematically represented as
![df = \frac{ [ \frac{s_1^2 }{n_1 } + \frac{s_2^2 }{n_2} ]^2 }{ \frac{1}{(n_1 - 1 )} [ \frac{s_1^2}{n_1} ]^2 + \frac{1}{(n_2 - 1 )} [ \frac{s_2^2}{n_2} ]^2 }](https://tex.z-dn.net/?f=df%20%3D%20%20%5Cfrac%7B%20%5B%20%5Cfrac%7Bs_1%5E2%20%7D%7Bn_1%20%7D%20%20%2B%20%5Cfrac%7Bs_2%5E2%20%7D%7Bn_2%7D%20%5D%5E2%20%7D%7B%20%5Cfrac%7B1%7D%7B%28n_1%20-%201%20%29%7D%20%5B%20%5Cfrac%7Bs_1%5E2%7D%7Bn_1%7D%20%5D%5E2%20%2B%20%5Cfrac%7B1%7D%7B%28n_2%20-%201%20%29%7D%20%5B%20%5Cfrac%7Bs_2%5E2%7D%7Bn_2%7D%20%5D%5E2%20%20%7D)
=> ![df = \frac{ [ \frac{5.9^2 }{34 } + \frac{4.4^2 }{34} ]^2 }{ \frac{1}{(34 - 1 )} [ \frac{5.9^2}{34} ]^2 + \frac{1}{(34- 1 )} [ \frac{4.4^2}{ 34} ]^2 }](https://tex.z-dn.net/?f=df%20%3D%20%20%5Cfrac%7B%20%5B%20%5Cfrac%7B5.9%5E2%20%7D%7B34%20%7D%20%20%2B%20%5Cfrac%7B4.4%5E2%20%7D%7B34%7D%20%5D%5E2%20%7D%7B%20%5Cfrac%7B1%7D%7B%2834%20-%201%20%29%7D%20%5B%20%5Cfrac%7B5.9%5E2%7D%7B34%7D%20%5D%5E2%20%2B%20%5Cfrac%7B1%7D%7B%2834-%201%20%29%7D%20%5B%20%5Cfrac%7B4.4%5E2%7D%7B%2034%7D%20%5D%5E2%20%20%7D)
=> 
Generally the standard error is mathematically represented as

=> 
=> 
From the question we are told the confidence level is 95% , hence the level of significance is

=> 
Generally from the t distribution table the critical value of at a degree of freedom of is

Generally the margin of error is mathematically represented as

=> 
=> 
Generally 95% confidence interval is mathematically represented as

=> 
=> 