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puteri [66]
2 years ago
14

Emma brought cookies to the dinner party! She made 50 cookies but

Mathematics
1 answer:
storchak [24]2 years ago
7 0

Answer:

The cookies Emma burnt are ten.

Step-by-step explanation:

You might be interested in
4x+12=−2x<br><br> i need help my stoopid math teacher is mean...
ehidna [41]

Answer:

-2=x

Step-by-step explanation:

4x+12=-2x

Subtract 4x on both sides

12=-6x

Divided by -6 on both sides

-2=x

3 0
3 years ago
The variable, y, varies directly with x. If y = 26 when x = 21,<br> what is y when x = 64?
STatiana [176]

Answer:

y=69

Step-by-step explanation:

first step:when y=26 and x=21

c=y-x

c=26-21

c=5

second step: when y is unknown and x=64

To find y we simply add the value of c to x

y=x+c

y=64+5

y=69

6 0
3 years ago
Represent Real-world Problems If one store is selling of a bushel of apples for $9, and another store is selling of a bushel of
Firlakuza [10]
Better deal normlly means the rate that cost less
rate=cost/amount

9=cost and 3/4 bushel = amount for one store
3/4=0.75
9/0.75=12/1 aka $12/1bushel

9 =cost and 2/3 bushel =amount for another
2/3=about 0.66666
9/0.66666=13.5/1 aka $13.5/1 bushell

compare
12 dollars per bushe vs 13.5 dollar per bushel
12 is cheaper

therefor $9 For 3/4 bushel is better deal
5 0
3 years ago
A textbook search committee is considering
lora16 [44]

Number of ways to select 3 books from 13 books for adoption is 286 .

<u>Step-by-step explanation:</u>

A Permutation is an ordered Combination. When the order does matter it is a Permutation. There are basically two types of permutation:

  • Repetition is Allowed: such as the lock above. It could be "333".
  • No Repetition: for example the first three people in a running race. You can't be first and second.

Formula is given by:

nC_r= \frac{n!}{r! (n-r)!} , where n is the number of things to choose from,  and we choose r of them,  no repetitions,  order matters. Here , n=13 , r=3.

⇒ 13C_3 = \frac{13!}{3!(13-3)!}

⇒ 13C_3 = \frac{13!}{3!(10)!}

⇒ 13C_3 = \frac{13(12)(11)10!}{3(2)(1)(10)!}

⇒ 13C_3 = 13(2)(11)

⇒ 13 C_3 = 286

∴ Number of ways to select 3 books from 13 books for adoption is 286 .

3 0
3 years ago
Anyone know this I’m stuck?
alexandr1967 [171]

Answer:

The answer is B.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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