Answer:
0 ≤ t ≤ 5.
Step-by-step explanation:
In the function 
, 
is the independent variable. The domain of 
is the set of all values of that this function can accept.
In this case, is defined in a real-life context. Hence, consider the real-life constraints on the two variables. Both time and volume should be non-negative. In other words,
.
.
The first condition is an inequality about , which is indeed the independent variable.
However, the second condition is about , the dependent variable of this function. It has to be rewritten as a condition about .
![\begin{aligned} f(t) &\ge 0 &&\text{Assumption} \cr 80000 - 16000\, t& \ge 0 && \text{Definition of} ~ f \cr 80000 & \ge 16000\, t && \begin{aligned}&\text{Add $16000\, t$} \\[-0.5em] & \text{to both sides of the inequality}\end{aligned} \cr 5 &\ge t &&\begin{aligned}&\text{Divide both sides of} \\[-0.5em] & \text{the inequality by $16000$}\end{aligned} \cr t &\le 5 && \text{Flip the inequality}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%20f%28t%29%20%26%5Cge%200%20%26%26%5Ctext%7BAssumption%7D%20%5Ccr%2080000%20-%2016000%5C%2C%20t%26%20%5Cge%200%20%26%26%20%5Ctext%7BDefinition%20of%7D%20~%20f%20%5Ccr%2080000%20%26%20%5Cge%2016000%5C%2C%20t%20%26%26%20%5Cbegin%7Baligned%7D%26%5Ctext%7BAdd%20%2416000%5C%2C%20t%24%7D%20%5C%5C%5B-0.5em%5D%20%26%20%5Ctext%7Bto%20both%20sides%20of%20the%20inequality%7D%5Cend%7Baligned%7D%20%5Ccr%205%20%26%5Cge%20t%20%26%26%5Cbegin%7Baligned%7D%26%5Ctext%7BDivide%20both%20sides%20of%7D%20%5C%5C%5B-0.5em%5D%20%26%20%5Ctext%7Bthe%20inequality%20by%20%2416000%24%7D%5Cend%7Baligned%7D%20%5Ccr%20t%20%26%5Cle%205%20%26%26%20%5Ctext%7BFlip%20the%20inequality%7D%5Cend%7Baligned%7D)
.
Hence, t ≤ 5.
Combine the two inequalities to obtain the domain:
0 ≤ t ≤ 5.
5/8=.625 and 7/15=.466 repeating so 5/8 is a bigger fraction
It will be option 3 so the answer is 1 quarts
Imagine a trigonometric circle with radius equal to 1.
We can say that the opposite side of the angle generated by the origin is equal to sen Ф and the adjacent equal to cos Ф
With this we can say that:
h² = c² + c²
If r = 1, then h = 1
1² = cos² + sen²
1 = cos² Ф + sen² Ф
You can use this equation a lot of times because it's the fundamental trigonometric relation
, so, when you something like:
sen Ф = cos Ф + 1
you can take from sen² Ф + cos² Ф = 1 that 
and then resolve.
Answer:
y=1/2x-5
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(1-(-2))/(12-6)
m=(1+2)/6
m=3/6
simplify
m=1/2
----------------------
y-y1=m(x-x1)
y-(-2)=1/2(x-6)
y+2=1/2(x-6)
y=1/2x-6/2-2
y=1/2x-3-2
y=1/2x-5
