The x² term will be C(5,2)x²·2³ = 80x².
The coefficient is 80.
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C(n, k) = n!/(k!·(n-k)!)
C(5, 2) = 5·4/(2·1) = 10
So since -2, 0, 1 are the roots:
Therefore x = -2, x = 0 , x = 1
Implies that:
x = 2 x - 2 = 0
x = 0 x = 0
x = 1 x - 1 = 0
Therefore (x - 2)x(x - 1) = 0
(x - 2)(x - 1) = x(x - 1) - 2(x - 1) = x² - x - 2x + 2 = x² - 3x + 2
(x - 2)x(x - 1) = 0
(x - 2)(x - 1)x = 0
(x² - 3x + 2)x = 0
x*x² - x*3x + x*2 = 0
x³ - 3x² + 2x = 0
This is the polynomial with the least degree, because it possible for another polynomial with higher power to still have the same root.
x³ - 3x² + 2x = 0 is the polynomial.
I hope this helps.
It’s C, because a square has 4 sides so you divide 25 by 4 and get 5
Our water faucet leaked 3 2/6 liters of water every 3/5 of a hour.
We are to find the rate in liter per hour at which the water faucet leaked.
First, use the number of liters the water faucet leaked in 3/5 of a hour.
This is 3 2/6 = 20/6
Therefore, the number of liters of water faucet leaked in 1 hour is
(20/6) / (3/5)
Before we solve this, we should simplify,
20/6 can be simplified to 10/3
3/5 cannot be simplified
Then, we should modify our problem to use reciprocation instead of a complex fraction,
(10 • 5) / (3 • 3)
This equals 50/9
Now, solve 50/9 for 5.555555555556
This rounds to 5.6
Thus, the required rate at which the water faucet leaked is 5.6 liters per hour.
