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3 years ago

Which of these characteristics does a rhombus have

Mathematics

2 answers:

iren2701 [21]3 years ago

5 0

Answer: opposite sides with equal length

Step-by-step explanation:

vodomira [7]3 years ago

3 0

Answer:

Opposite sides with equal length

Step-by-step explanation:

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Identify the slope and y-intercept of the line for each equation: y = 1/4x + 5

Tasya [4]

Answer:

the given equation is

y= 1÷4x +5

now,

slope = 1÷4

and

y intercept= - 5÷ 1÷4

= -5÷ 4

6 0

2 years ago

The product of two numbers is 41. One of the numbers

shepuryov [24]

<h3>Answer: 5 - 4i (choice A)</h3>

===================================================

Work Shown:

x = the other number

(5+4i)*x = 41

x = 41/(5+4i)

x = 41*(5-4i)/( (5+4i)*(5-4i) ) ..... see note below

x = 41*(5-4i)/( 41 )

x = (41/41)*(5-4i)

x = 5 - 4i

As a way to check, (5+4i)*(5-4i) = 5^2+4^2 = 25+16 = 41

The rule used is (a-bi)(a+bi) = a^2 + b^2

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Note: I multiplied top and bottom by (5-4i) to get rid of the imaginary term in the denominator.

3 0

3 years ago

Can someone help me with this please ?

rusak2 [61]

38 , because since its 90 degrees at exact, your subtract 90 from 52 and you would get 38 for your x value

8 0

3 years ago

preliminary sample of 100 labourers was selected from a population of 5000 labourers by simple random sampling. It was found tha

VladimirAG [237]

Answer:

$n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79$

n=369

Step-by-step explanation:

1) Notation and definitions

$X=40$ number of the selected labourers opt for a new incentive scheme.

$n=100$ random sample taken

$\hat p=\frac{40}{100}=0.4$ estimated proportion of the selected labourers opt for a new incentive scheme.

$p$ true population proportion of the selected labourers opt for a new incentive scheme.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

2) Solution tot he problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: