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hammer [34]
3 years ago
9

A college raises its tuition in each of three consecutive years. If the percent increase by 5%, 9%, and 7%, determine the overal

l percent increase at the end of the three-year period?
Mathematics
1 answer:
agasfer [191]3 years ago
7 0

The overall percentage increase is 22.5%.

s<u>tep-by-step explanation</u>

Percentage increase in the first year=5%

Percentage increase in the second year=9%

Percentage increase in the third year=7%

we have to calculate the overall percentage increase

Let  the initial tuition fees be x

tuition fees after three years=

=x\times \frac{100+a}{100} \times\frac{100+b}{100}\times \frac{100+c}{100} \\=x\times \frac{105}{100} \times\frac{109}{100} \times\frac{107}{100} \\\\=x\times \frac{1224615}{1000000} \\=x\times\frac{122.4625}{100} \\=x\times\frac{100+22.4625}{100}

The overall percentage increase is 22.5%.

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Step-by-step explanation:

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3 years ago
What is the area of the sector of a circle with radius r=2 cm, and the measure of its intercepted arc of 150 degrees ?
AURORKA [14]
There are is 160 metres squared is the answer to this question
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2 years ago
Which describes the relationship between ZNOM and ZJOK in the diagram?
sveta [45]

Answer:

the anwser is: B: Supplementary Angles

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7 0
3 years ago
Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How
HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that \mu = 5.2r, in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

P(X \geq 1) = 1 - P(X = 0) = 0.99

Thus:

P(X = 0) = 1 - 0.99 = 0.01

We have that:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}

Then

e^{-5.2r} = 0.01

\ln{e^{-5.2r}} = \ln{0.01}

-5.2r = \ln{0.01}

r = -\frac{\ln{0.01}}{5.2}

r = 0.89

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0
3 years ago
Jack and Jim sign up with an online music store. Jack chooses 15 downloads for $19.75, and Jim chooses 40 downloads for $43.50.
lina2011 [118]
The answer would be A. <span>The registration fee is $5.50, and the cost per download is $0.95.</span>

Solution
Let x = registration fee
y = cost/downloads

Jack
15y + x = 19.75 ; x = 19.75 - 15y
Jim
40y + x = 43.50

Thus,
40y + x = 43.50
40y + <span>19.75 - 15y = 43.50
</span>25y = 23.75
y= 0.95

for x,
<span>x = 19.75 - 15y</span>
x = 19.75 - 15( 0.95)
x= 19.75 -14.25
x = 5.5
3 0
3 years ago
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