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Tcecarenko [31]
3 years ago
5

PLS HELP BRAINLIEST !!!! BE SERIOUS PLS dont want to report anyone :((

Mathematics
2 answers:
4vir4ik [10]3 years ago
8 0

Answer:

Step-by-step explanation:

LAST ONE

DanielleElmas [232]3 years ago
8 0

I say the answer would be No because the triangles are not the same Width, length or height..

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Consider the reaction. Upper n subscript 2 (g) plus 3 upper H subscript 2 (g) double-headed arrow 2 upper N upper H subscript 3
umka2103 [35]

The equilibrium constant of the reaction is 0.0030.

The equation of the reaction is given as;

N2(g) + 3H2(g) ⇆ 2NH3 (g)

We have the following information at equilibrium;

[NH3] = 0.105 M

[N2] = 1.1 M

[H2] = 1.50 M

Hence, we can calculate the equilibrium constant using the relation;

K = [NH3]^2/ [N2]  [H2]^3

Substituting values;

K = [0.105]^2/[ 1.1] [1.50]^3

K =0.011025 /3.7125

K= 0.0030

Learn more: brainly.com/question/17960050

3 0
2 years ago
Ryan made a 3250 down payment on a car. The total coast of the car was 28500. He made 36 equal monthly payments to pay the car i
GuDViN [60]

Answer:

Step-by-step explanation:

28500-3250= 25250 se resta el pago inicial

25250/36 =701.38 pesos mensuales

7 0
3 years ago
How do you graph lines using intercepts<br> Ex. 3y= 1/2x-2 (How would you graph that?)
scZoUnD [109]
Read this article https://weteachscience.org/mentoring/resources/lesson-plans/algebra-1-%E2%80%93-how-to-graph-a-linea...

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4 years ago
Last week Bryan traveled 4 miles by a bus, 18 miles by a train, 11 miles by a van, 33 miles by a car, 7 miles by a bike and walk
kvv77 [185]

Answer:

\boxed{\text{[2, 33]}}

Step-by-step explanation:

The range is the spread of the y-values (minimum to maximum distance travelled).

The minimum is 2 mi, and the maximum is 33 mi, so the range is from 2 to 33.

In interval notation, the range is \boxed{\textbf{[2, 33]}}

6 0
4 years ago
Read 2 more answers
Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)
USPshnik [31]

First, expand the terms inside the bracket you will get

(( \tan {}^{2} (x)  + 2 \tan(x)  \sin(x)  +  \sin {}^{2} (x)  - ( \tan {}^{2} (x)  - 2 \tan(x)  +  \sin {}^{2} (x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

( 4 \tan(x)  \sin(x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x)  \sin {}^{2} (x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x) (1 -  \cos {}^{2} (x) ) = 16 (\tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan {}^{2} (x)  -   \frac{  \sin {}^{2} (x) \cos {}^{2} ( {x}^{} )  }{ \cos {}^{2} (x) }

16( \tan {}^{2} (x)  -  \sin {}^{2} (x) ) = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

5 0
2 years ago
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