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borishaifa [10]
3 years ago
15

Pleaseeeeeee help meeeeeeeeeee

Mathematics
1 answer:
vladimir1956 [14]3 years ago
8 0
The answer is -10u you add and subtract the like terms
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Which graph shows x =4?
ZanzabumX [31]

Answer:

second graph shows x=4 because you can see from origin point and counting will makex=4

3 0
3 years ago
Please help me! This is a grade
arlik [135]

Answer:

7^4

7 to the fourth power

7 ·7·7·7

Step-by-step explanation:

Because 7 to the fourth power is 7^4  and that equals 7·7·7·7

3 0
3 years ago
(05.05 LC)
Phantasy [73]

Answer:

A. $6

Step-by-step explanation:

We are given the table representing the number of days and the total charges in dollars.

So, the rate of change of the amount is given by, \frac{16-6}{1-0}=\frac{26-16}{2-1}=10

The linear equation representing the situation is,

Total charges = Fee per days + Fixed amount.

i.e. Total charges, y = Rate multiplied by x + Fixed amount (c)

So, substituting the rate and the point (0,6), we get,

6 = 10 × 0 + c

i.e. c = 10

Thus, the equation is,

Total charges, y = Rate multiplied by x + Fixed amount (c)

i.e. y = 10x + 6

Hence, the fixed amount charged is $6.

So, option A is correct.

4 0
3 years ago
My son is seven times older than my grandson and I am 12 times older than my grandson. If you add all our ages together, the sum
Andrej [43]
To solve this problem you first need to establish what it is you are looking for.. if you knew the grandson age then you could find your son and you.  So that is what we need to find and since we don't know it, we will call it x.

Grandson = x
Son = 7x
You = 12x

Then it says the sum of the 3 is 100.... x + 7x + 12x = 100 then solve and find that x = 5.  So to determine your age, just put 5 in for x and you get 60... dang your old ha
7 0
3 years ago
Expand the given power by using Pascal’s triangle. (9a - 10b)^6
xxMikexx [17]

Answer:

531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

Step-by-step explanation:

                     1                                n=0

                  1      1                            n=1

                 1   2   1                           n=2

                1  3  3  1                          n=3

              1  4  6  4   1                      n=4

             1  5 10 10 5  1                    n=5

           1 6 15 20 15 6 1                   n=6

This is where n is the exponent in

(x+y)^n.

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

Now we want to expand:

(9a-10b)^6 or we we can rewrite as (9a+(-10b))^6.

Let's replace x with (9a) and y with (-10b) in the expansion:

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

((9a)+(-10b))^6

=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6

Let's simplify a bit:

=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6

=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

8 0
3 years ago
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