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kkurt [141]
3 years ago
9

0,0a_2×1÷4=12÷10a_52÷10

Mathematics
1 answer:
kozerog [31]3 years ago
8 0

Answer:

19/4

Step-by-step explanation:

0.5=12/10a-5.2

1/2=6/5a-26/5

5=12a-52

-12a=-57

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(3x+14)° measurement in degrees a.20.00° b.40.25° c.42.50° d.74.00°​
Marysya12 [62]

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B

Step-by-step explanation:

4 0
2 years ago
A slug travels 3 centimeters in 3 seconds. A snail travels 6 centimeters in 6 seconds Both travel at constant speeds. Mai says,
Mashutka [201]

Answer:

No I dont agree with Mai. As both the slug and snail are moving with constant speed.

Step-by-step explanation:

Given that:

A slug travels 3 centimeters in 3 seconds.

Speed of slug = distance/ time = 3/3 = 1 cms^-1

A slug travels 3 centimeters in 3 seconds.

Speed of snail = distance/ time = 6/6 = 1 cms^-1

Hence both have constant speeds only the time span for snail is increased which gives more distance it doesn't means that it had covered more distance.

i hope it will help you!

4 0
3 years ago
What is the slope of a line perpendicular to the
Dahasolnce [82]

Answer: a. -3/5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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Harman [31]

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+7

Step-by-step explanation:

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6 0
3 years ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
Maru [420]

Parameterize S{/tex] by[tex]\vec s(u,v)=u\,\vec\imath+v\,\vec\jmath+(8-u^2-v^2)\,\vec k

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Take the normal vector to S to be

\vec s_u\times\vec s_v=2u\,\vec\imath+2v\,\vec\jmath+\vec k

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(uv\,\vec\imath+v(8-u^2-v^2)\,\vec\jmath+u(8-u^2-v^2)\,\vec k)\cdot(2u\,\vec\imath+2v\,\vec\jmath+\vec k)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1\bigg(2u^2v+(u+2v^2)(8-u^2-v^2)\bigg)\,\mathrm du\,\mathrm dv=\boxed{\frac{1553}{180}}

6 0
3 years ago
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