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Marrrta [24]
2 years ago
8

Girardo is using the model below to solve the equation 3x+1=4x+(-4)

Mathematics
1 answer:
V125BC [204]2 years ago
5 0

Answer:

x=5

Step-by-step explanation:

3x+1= 4x+(-4)

-4×+1= -4x-1 combine like terms

-1x= -5 divided by -1

x= 5

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2 years ago
I pay 25,000 for a car it depreciates at a rate of 10% what is the value of the car in 7 year
Murrr4er [49]

Answer:

2500

Step-by-step explanation:

7 0
3 years ago
14. Write a two-column proof.
scZoUnD [109]

Given:

\bold{ 8x=4y-20} \\\\ \bold{ y=13}

Prove:

\bold{x=4}

Solution:

\to \bold{8x=4y-20}..........(i)\\\\\to \bold{ y=13}........................(ii)

Putting the value of equation (ii) into the equation (i):

\to \bold{8x=4(13)-20}\\\\\to \bold{8x=52-20}\\\\\to \bold{8x=32}\\\\\to \bold{x=\frac{32}{8}}\\\\\to \bold{x= 4}\\\\

putting the value x into the equation (i):

\to \bold{8(4)=4y-20}\\\\\to \bold{32=4y-20}\\\\\to \bold{32+20=4y}\\\\\to \bold{52=4y}\\\\\to \bold{y=\frac{54}{4}}\\\\\to \bold{ y= 13.5}

Therefore, the value of x= 4

Learn more:

brainly.com/question/6219408

3 0
2 years ago
3(x^2-1) + 4(x^2 - 3) = 13<br><br> solve for x
Mrrafil [7]

Answer:

x=2, x=-2

Step-by-step explanation:

3x²-3+4x²-12=13

7x²=13+12+3

7x²=28

x²=4

x=-2

x=2

4 0
3 years ago
Read 2 more answers
Determine where V(z)=z4(2z−8)3 is increasing and decreasing.
Marat540 [252]

Answer and Explanation:

A function is said to be increasing, if the derivative of function is f’(x) > 0 on each point. A function is said to be decreasing if f”(x) < 0.

Let y = v (z) be differentiable on the interval (a, b). If two points z1 and z2 belongs to the interval (a, b) such that z1 < z2, then v (z1) ≤ v (z2), the function is increasing in this interval.

Similarly, the function y = v(z) is said to be decreasing, when it is differentiable on the interval (a , b).

Two points z1 and z2 Є (a, b) such that z1 > z2, then v (z1) ≥ v(z2). The function is decreasing on this interval.

The function y = v (z)

The derivative of function Y’ = v’(z) is positive, then the function is increasing.

The function y = v (z)  

The derivative of function y’ is negative, then the function is decreasing.

8 0
3 years ago
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