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Phantasy [73]
3 years ago
8

Classify the system of equations 1/3x+y+5=0 1/2x+y-3=0

Mathematics
1 answer:
Pavel [41]3 years ago
6 0

Answer: Consistent and Independent.


Step-by-step explanation:

1. To solve this problem and classify the system of equations shown above, you can graph it has you can see in the graph attached.

2. As you can observe in the graph the lines intersect each other, this means that the system of equation has one solution.

3. By definition, when a system of equations has one solution, it is classified as Consistent and Independent.

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The question= find the percent of each number
RUDIKE [14]

Answer:

78 x 160 /100

= 124.8

12 x 325/100

= 39

Step-by-step explanation:

6 0
3 years ago
Can i get help with 4,6, and 8 PLEASE HELP!!!!!!!!!! IM GONNA RUN OUTTA TIME!!!!
gogolik [260]
They are all even numbers
8 0
3 years ago
Prove the following statement.
jolli1 [7]
<h2>Step-by-step explanation:</h2>

As per the question,

Let a be any positive integer and b = 4.

According to Euclid division lemma , a = 4q + r

where 0 ≤ r < b.

Thus,

r = 0, 1, 2, 3

Since, a is an odd integer, and

The only valid value of r = 1 and 3

So a = 4q + 1 or 4q + 3

<u>Case 1 :-</u> When a = 4q + 1

On squaring both sides, we get

a² = (4q + 1)²

   = 16q² + 8q + 1

   = 8(2q² + q) + 1

   = 8m + 1 , where m = 2q² + q

<u>Case 2 :-</u> when a = 4q + 3

On squaring both sides, we get

a² = (4q + 3)²

   = 16q² + 24q + 9

   = 8 (2q² + 3q + 1) + 1

   = 8m +1, where m = 2q² + 3q +1

Now,

<u>We can see that at every odd values of r, square of a is in the form of 8m +1.</u>

Also we know, a = 4q +1 and 4q +3 are not divisible by 2 means these all numbers are odd numbers.

Hence , it is clear that square of an odd positive is in form of 8m +1

3 0
3 years ago
Another geometry question♥♥
storchak [24]
Set the 2x - 1 equal to 9 then work backwards. 2x - 1 = 9 Nine minus one is eight divided by two is four. X = 4
4 0
3 years ago
How do I find the area of the shaded region? Thanks!!
bazaltina [42]

Answer:

The radius of a circumcircle of an equilateral triangle is equal to (a / √3), where ‘a’ is the length of the side of equilateral triangle.

Circle Radius = 16 / sq root (3)

Circle Radius = 9.237604307

Circle Area = PI * radius ^ 2

Circle Area = PI * 85.3333333333

Circle Area = 268.083

Equilateral Triangle area = side^2 * sq root (3) / 4

Equilateral Triangle area = 16^2 * 0.4330127019

Equilateral Triangle area = 110.85

Shaded region = 268.083 - 110.85

Shaded region = 157.233

Step-by-step explanation:

7 0
3 years ago
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