It is 54 degrees (fifty four)
Answer:
Bottom left choice
Step-by-step explanation:
SSS congruence is side-side-side congruence, which is a method to prove triangles congruent by all three sides of the triangle being congruent. The other choices all involve congruent angles. Therefore, the bottom left choice is the best answer.
Also, notice that the bottom left choice shows which side is congruent to which. All three sides of one of the triangles are shown to be congruent with the corresponding side to the other triangle, therefore, congruent by SSS.
I hope this helps! :)
Let's solve your inequality step-by-step.
5m<6m+6
Step 1: Subtract 6m from both sides.
5m−6m<6m+6−6m
−m<6
Step 2: Divide both sides by -1.
−m / −1 < 6 / −1
m>−6
Answer:
m>−6
<h3>☂︎ Answer :- </h3>
<h3>☂︎ Solution :- </h3>
- LCM of 5 , 18 , 25 and 27 = 2 × 3³ × 5²
- 2 and 3 have odd powers . To get a perfect square, we need to make the powers of 2 and 3 even . The powers of 5 is already even .
In other words , the LCM of 5 , 18 , 25 and 27 can be made a perfect square if it is multiplied by 2 × 3 .
The least perfect square greater that the LCM ,
☞︎︎︎ 2 × 3³ × 5² × 2 × 3
☞︎︎︎ 2² × 3⁴ × 5²
☞︎︎︎ 4 × 81 × 85
☞︎︎︎ 100 × 81
☞︎︎︎ 8100
8100 is the least perfect square which is exactly divisible by each of the numbers 5 , 18 , 25 , 27 .
The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.
Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.
So, if we sum the first N odd numbers, we have
The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have
The second sum is simply the sum of N ones:
So, the final result is
which ends the proof.
