Answer: Therefore, the x-intercept of the line is 0
A line with slope 2/3 contains the point P(-18, -12). What is the x intercept of the line?
Step-by-step explanation:
Given;
Slope m = 2/3
Straight line equation is given as
y = mx+c
Where m = slope and c = intercept on y axis
For this case,
y = 2/3x + c .....1
At point (-18,-12), Eqn 1 becomes;
-12 = 2/3(-18) + c
-12 = -12 + c
c = 0
The straight line equation becomes
y = 2/3x + 0
Therefore at y = 0 the value of x = 0
Therefore the intercept is at (0,0)
Therefore, the x-intercept of the line is 0
Y-intercept is 5 and slope 11
No. 6/8=9/12
by multiplying the denominators you get the common denominator of 72
then multiply each numerator by the number of the opposite denominator
8x12=96
6x12=72
9x8=72
Therefore, 72/96=72/96
(6/8 = 9/12)
For a triangle, there is a proven inequality<span> that states that</span><span>, the sum of the lengths of any two sides must be greater than or equal to the length of the remaining side
21 + 37 >= 15
58 >= 15
21 + 15 >= 37
36 >= 37
37 + 15 >= 21
52 >= 21
We can see that the second inequality doesn't comply, thus there is not such triangle.</span>
Answer:
i dont know if this is what u wanted but it wasn't really specified
Step-by-step explanation:
1(4 – 22); 2 – 2x
simplified:
−18;−2x+2
