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scoray [572]
3 years ago
12

Round to the nearest tenths please txt bck faster

Mathematics
1 answer:
adell [148]3 years ago
5 0
Answer:

Sides:
a = 16 in
b = 10.28 in
c = 12.26 in

Angles:
A = 90 °
B = 40 °
C = 50 °

Other:
P = 38.541312844888 in
s = 19.270656422444 in
K = 63.027696192781 in2
r = 3.2706564224441 in
R = 8 in

Table:
A = angle A
B = angle B
C = angle C
a = side a
<span>b = side b </span>
c = side c

P = perimeter
<span>s = semi-perimeter </span>
K = area
r = radius of inscribed circle
<span>R = radius of circumscribed circle</span>
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Consider the system of equations.
Harman [31]

The solution to the system of equations x + 2y = 1  and -3x-2y = 5 is:

x  = -3,  y = 2

The given system of equations:

x  +  2y  =  1............(1)

-3x - 2y  =  5..........(2)

This can be written in matrix form as shown:

\left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]

Find the determinant of \left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right]

\triangle = 1(-2) - 2(-3)\\\triangle = -2+6\\\triangle  = 4

\triangle_x = \left[\begin{array}{ccc}1&2\\5&-2\end{array}\right]\\\triangle_x = 1(-2)-2(5)\\\triangle_x = -2-10\\\triangle_x =-12

\triangle_y = \left[\begin{array}{ccc}1&1\\-3&5\end{array}\right]\\\triangle_y = 1(5)-1(-3)\\\triangle_y = 5 + 3\\\triangle_y =8

x = \frac{\triangle_x}{\triangle} \\x = \frac{-12}{4} \\x = -3

y = \frac{\triangle_y}{\triangle} \\y = \frac{8}{4} \\y = 2

The solution to the system of equations x + 2y = 1  and -3x-2y = 5 is:

x  = -3,  y = 2

Learn more here: brainly.com/question/4428059

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2 years ago
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