What are hydrogen particles

There are 12 inches (in). in 1 foot (ft). which expression can be used to find the number of inches in 2.5 feet?

Nady [450]

Given:
12 inches in 1 foot
number of inches in 2.5 feet

2.5 feet * 12 inches/1foot = 2.5 * 12 inches = 30 inches

1 foot + 1 foot + 0.5 foot = 2.5 feet
12 inches + 12 inches + 6 inches = 30 inches

12 inches : 1 foot = x : 2.5 feet
12 inches * 2.5 feet = x*1foot
30 inches * feet = x * foot
30 inches = x

4 0

3 years ago

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What is the total energy change for the following reaction:CO+H2O-CO2+H2

Alekssandra [29.7K]

Answer:

$\large \boxed{\text{-41.2 kJ/mol}}$

Explanation:

Balanced equation: CO(g) + H₂O(g) ⟶ CO₂(g) + H₂(g)

We can calculate the enthalpy change of a reaction by using the enthalpies of formation of reactants and products

$\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)$

(a) Enthalpies of formation of reactants and products

$\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{CO(g)} & -110.5 \\\text{H$_{2}$O} & -241.8\\\text{CO$_{2}$(g)} & -393.5 \\\text{H$_{2}$(g)} & 0 \\\end{array}$

(b) Total enthalpies of reactants and products

$\begin{array}{ccr}\textbf{Substance} & \textbf{Contribution)/(kJ/mol})&\textbf{Sum} \\\text{CO(g)} & -110.5& -110.5 \\\text{H$_{2}$O(g)} &-241.8& -241.8\\\textbf{Total}&\textbf{for reactants} &\mathbf{ -352.3}\\&&\\\text{CO}_{2}(g) & -393.5&-393.5 \\\text{H}_{2} & 0 & 0\\\textbf{Total}&\textbf{for products} & \mathbf{-393.5}\end{array}$

(c) Enthalpy of reaction $\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)= \text{-393.5 kJ/mol - (-352.3 kJ/mol}\\= \text{-393.5 kJ/mol + 352.3 kJ/mol} = \textbf{-41.2 kJ/mol}\\ \text{The total enthalpy change is $\large \boxed{\textbf{-41.2 kJ/mol}}$}$

4 0

3 years ago

Arrange the following compounds in order of increasing acidity, and explain the reasons for your choice of order. a. 2,4-dinitro

ludmilkaskok [199]

Compounds in order of increasing acidity will be written as d<c<b<a.

<h3>What is acidity?</h3>

The quantity of hydroxyl ions that a basic molecule may create in an aqueous solution is what is known as the acidity of bases. The quantity of hydronium ions that a substance may create in an aqueous solution determines how basic an acid is.

a, b are more acidic than c and d because of OH group attached to sp2 hybridised carbon which provide resonance stability for conjugate base

in c f has -I effect which increases acidity in a, NO2 has -m effect which increases acidity so increasing order is d<c<b<a

that is cyclohexanol < 2,4-difluorocyclohexanol < phenol < 2,4-dinitrophenol

to learn more about acidity go to -

brainly.com/question/19584961

#SPJ4

3 0

2 years ago

Please help will give brainliest to best answer

Stolb23 [73]

Answer:

A student wrapped in a blanket or siting in the hot sun or showering with hot water

Explanation:

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3 years ago

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A standard solution is prepared for the analysis of fluoxymesterone (C20H29FO3), an anabolic steroid. A stock solution is first

VLD [36.1K]

Answer:

The final solution has a concentration of 5.95 * 10^-6 M

Explanation:

<u>Step 1:</u> data given

Mass of fluoxymesterone : 10mg = 0.01g

Molar mass of fluoxymesterone = 336g/mole

Volume = 500 mL =0.5 L

<u>Step 2:</u> calculate Concentration of fluoxymesterone

Concentration = mole / volume

⇒ To find the concentration, we first need to find the number of moles

⇒moles fluoxymesterone= mass of fluoxymesterone / Molar mass

0.01g / (336g/mole) = 2.976 *10^-5 mole

C = 2.976 *10^-5 mole / 0.5 L = <u>5.95 * 10 ^-5 M</u>

<u>Step 3:</u> Calculate dilution

⇒ If 10 mL is diluted to 100 ml then this is a 10x dilution (100 ml /10 ml = 10) so the final solution will be 10 x more dilute.

⇒5.95 * 10^-5 M /10 = 5.95 ^* 10^-6 M

We can control this through the following formula: M1 * V1 = M2 * V2

5.95 *10^-5 * 10 * 10 *^-3 = M2 *0.1 L

M2 = 5.95 * 10^-6 M

6 0

4 years ago