Answer:
The area of the triangle is 351cm^2.
Step-by-step explanation:
To find the area of a triangle, the formula is (1/2) x base x height. In this case, the height would be a line that cuts straight through the center of the triangle. However, this height is not given to us. We can still find it through Pythagoras' Theorem though.
Let A be the tip of the triangle, and B and C be the points on either side of the triangle. Assuming an imaginary line that cuts the triangle in a symmetrical half, let T be the point at the end of the line, directly below point A.
Using Pythagoras' Theorem,
AB^2 = AT^2 + TB^2
AT^2 = AB^2 - TB^2
AT^2 = 30^2 - (26/2)^2
AT^2 = 30^2 - 13^2
AT =

AT = 27.0370116692
So the length of AT is our height. We can now find the area of the triangle.
Area of triangle = (1/2) x 26cm x AT
Area of triangle = 351.4811516996
Area of triangle = 351cm^2 (To 3s.f.)
=1/2
you add both on each side then subtract 2 from you anser
Answer:
= 1.75
Step-by-step explanation:
7/6 divided by 6
= 7/36
7/36 = x/9
Cross multiply fractions:
36x = 63
Divide each side by 36:
x = 7/4 or 1.75
<h3>
Answer: True</h3>
Explanation:
This theorem doesn't have a name unfortunately. So searching it out is a bit tricky if you don't know the right way to word things. Luckily it wasn't too hard of a find, and I managed to track it down in a linear algebra textbook.
Check out the screenshot below for the snippet of the theorem and the corresponding proof. The book simply refers to it as "theorem 1.9", which again, is an unfortunate choice of naming.