P=28 in
l=3*w-2
p=2w+2l
p=2w+2*(3w-2)
p=2w+6w-2*2
p=8w-4
p=28 in
8w-4=28
8w=28+4
8w=32 in
w=32/8=4 in
l=3*4-2=12-2=10 in
Answer:
12 inches
Step-by-step explanation:
Raj tested his new flashlight by shinning it on his bedroom wall the beam of the light can be described by the equation (x^2-2x) + (y^2-4y) - 31=0. how many inches wide is the beam of light on the wall
Solution
Given:
(x^2-2x) + (y^2-4y) - 31=0
By completing the square
(x^2-2x) + (y^2-4y) - 31=0
(x^2-2x+1-1) + (y^2-4y+4-4)-31=0
(x-1)^2 -1 + (y-2)^2 - 4 - 31=0
(x-1)^2 + (y-2)^2 - 1 - 4 - 31=0
(x-1)^2 + (y-2)^2 - 36=0
(x-1)^2 + (y-2)^2=36
Writing the equation in the form: (x-h)^2+(y-k)^2=r^2
(x-1)^2+(y-2)^2=6^2
From the above, r=6
Where,
r=radius
how wide is the diameter ?
radius=6
Diameter= 2 × radius
=2×6
=12 inches
x + x+1 + x+2 =81
Simplify:
3x + 3 = 81
Subtract 3 from both sides
3x = 78
Divide both sides by 3
x = 26 or C). 26
Your awnser is a because 192x6=1152.
