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Triss [41]
2 years ago
5

the diagram below shows a trapezium. all the measurements are in centimetres. the area of the trapezium is 30 cm^2 l. Set up and

solve a quadratic equation to work out the value of x

Mathematics
1 answer:
erica [24]2 years ago
5 0

Answer:

x²+x-30

x=5

Step-by-step explanation:

The equation is

(x+3+x-1)/2 × x=30

x²+x-30 (it's the quadratic equation)

x²+6x-5x-30=0

x(x+6)-5(x+6)=0

(x+6)(x-5)=0

x=-6

x=5

It's impossible for Length to be negative

So x=5

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-BARSIC- [3]

Answer:

x-intercept - x = 1/2y - 3.15

y-intercept - y = 2x + 6.3

Step-by-step explanation:

For x,

-6x + 3y = 18.9

-6x = -3y + 18.9

x = -3y/-6 + 18.9/-6

x = 1/2y - 3.15

For y,

-6x + 3y = 18.9

3y = 6x + 18.9

y = 6x/3 + 18.9/3

y = 2x + 6.3

8 0
2 years ago
The rectangular field has a perimeter of 98 meters. The width of the perimeter is three times as much as five times the length.
White raven [17]

Answer:

a) x = 3.0625m

  y = 45.9375 m

b) A = 140.68359375 m²

Step-by-step explanation:

Let x be the length

Let y be the width

2x + 2y = 98

x + y = 49

y = 3(5x)

y = 15x

x + 15x = 49

16x = 49

x = 3.0625 m

y = 15(3.0625) = 45.9375

A = xy = 3.0625(45.9375) = 140.68359375

4 0
3 years ago
Which of the following congruency statements is correct? Yzx = bcd, yzx = dcb, zxy =dcb, yxz = cdb
goldenfox [79]

Answer:c

Step-by-step explanation:

7 0
2 years ago
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A speed limit is 35 mph. A car is travelling 10 mph over the speed limit. I’d that a sum of 0
max2010maxim [7]

Answer:

The car is going 45 mph

Step-by-step explanation:

Since the speed limit is 35 mph and the car is 10 mph over the speed, we can add them to find out how fast the car is going. We can solve 35+10 which will give us 45. So it is not a sum of 0 but instead a sum of 45.

(hope this helped)

5 0
3 years ago
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PLEASE HELP ME I DONT UNDERSTAND
drek231 [11]

Answer:

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Step-by-step explanation:

"The quotient" means that it is a division problem. That means you have to divide.

Less than is a symbol that stands for *The number is less than the other number*

3 0
3 years ago
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