Answer:
A. 0.0450
B. 4
C. 0.25
D. 37.68
E. 6Hz
F. -0.523
G. 1.5m/s
H. vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)
I. -1.67m/s.
Explanation:
Given the equation:
y(x,t) = 0.0450 sin(25.12x - 37.68t-0.523)
Standard wave equation:
y(x, t)=Asin(kx−ωt+ϕ)
a.) Amplitude = 0.0450
b.) Wave number = 1/ λ
λ=2π/k
From the equation k = 25.12
Wavelength(λ ) = 2π/25.12 = 0.25
Wave number (1/0.25) = 4
c.) Wavelength(λ ) = 2π/25.12 = 0.25
d.) Angular frequency(ω)
ωt = 37.68t
ω = 37.68
E.) Frequency (f)
ω = 2πf
f = ω/2π
f = 37.68/6.28
f = 6Hz
f.) Phase angle(ϕ) = -0.523
g.) Wave propagation speed :
ω/k=37.68/25.12=1.5m/s
h.) vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)
(i) vy(3.5m, 21s) = 0.045(-37.68) cos (25.12*3.5-37.68*21-0.523) = -1.67m/s.
Answer:
Uhyuuuuufuddirueueurururururru
Answer:
- The graph of the function is attached below.
- The x-intercepts will be: (2, 0), (-2, 0)
- The y-intercept will be: (-20, 0)
Explanation:
Given the function
As we know that the x-intercept(s) can be obtained by setting the value y=0
so
switching sides
Add 20 to both sides
Dividing both sides by 5
so the x-intercepts will be: (2, 0), (-2, 0)
we also know that the y-intercept(s) can obtained by setting the value x=0
so
so the y-intercept will be: (-20, 0)
From the attached figure, all the intercepts are labeled.
Answer:
They are both ways to identify assets (e.g., persons, animals, objects).
Explanation:
A barcode is a bit of information (usually a number) printed as a line or block pattern on a surface (e.g., a sticker).
An RFID is a bit of computer memory with an antenna.
Both can be read with the appropriate scanner device.
