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anygoal [31]
2 years ago
9

Una familia está conformada por el padre, la madre, el hijo y la hija, el padre tiene el doble de la edad del hijo, la madre tie

ne 6 años menos que el padre, la hija tiene 5 años más que el hijo. sumando sus edades dan 106. calcular que edad tienen cada uno.
Mathematics
2 answers:
Jlenok [28]2 years ago
8 0

Answer:

PADRE=36 AÑOS - MADRE=30 AÑOS - HIJA=23 AÑOS - HIJO= 18 AÑOS

Mariulka [41]2 years ago
3 0

Answer:

Step-by-step explanation:

First off, this wouldn't make sense for a girl to be older than her mother or her father.

Second, mother is x years old. The girl is 2x years old. The father is x+5 years old. Total sum = 100.

So, we need to solve for x first.

2x + x + x+5 = 100

4x + 5 = 100

4x = 95

4x ÷ 4 = 95 ÷ 4

x = 23.75

Mother is 23 and 3 quarters, turning 24.

Daughter is 23.75 × 2 = 47 1/2 years old.

And the Father is 28 and 3 quarters, turning 29.

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Answer:

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Step-by-step explanation:

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Now, if we compute the n-th derivative at 0 we get

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and so the Maclaurin series for f(x)=ln(1+2x) is given by

f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2  \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}

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