Answer:
Step-by-step explanation:
(2-3)⁴ *4 - 9 + 3 = (-1)⁴ *4 - 9 + 3
= 1*4 - 9 +3
= 4 - 9 + 3
= - 5 + 3
= - 2
Answer:
The ira will contain $228,278.05 when he retires at age 65. This is 6.04 times the amount of money he deposited.
Step-by-step explanation:
In order to solve this problem, we can make use of the following formula:
![FV=PMT[\frac{(1+i)^{n}-1}{i}]](https://tex.z-dn.net/?f=FV%3DPMT%5B%5Cfrac%7B%281%2Bi%29%5E%7Bn%7D-1%7D%7Bi%7D%5D)
Where:
FV= Future value of the ira
PMT= the amount of money you deposit each month
i= is the interest rate per period
n=number of periods
in this case we will assume the interest will be compounded each month.
So:
FV this is what we need to know.
PMT= $75 the amount he will deposit each month
t = 42 years,
this is 65-23=42
n=42 years * 12 months/year = 504 months
i=0.07/12
So we can now use the given formula:
![FV=PMT[\frac{(1+i)^{n}-1}{i}]](https://tex.z-dn.net/?f=FV%3DPMT%5B%5Cfrac%7B%281%2Bi%29%5E%7Bn%7D-1%7D%7Bi%7D%5D)
![FV=75[\frac{(1+\frac{0.07}{12})^{504}-1}{\frac{0.07}{12}}]](https://tex.z-dn.net/?f=FV%3D75%5B%5Cfrac%7B%281%2B%5Cfrac%7B0.07%7D%7B12%7D%29%5E%7B504%7D-1%7D%7B%5Cfrac%7B0.07%7D%7B12%7D%7D%5D)
So we get:
FV=$228,278.05
which is the amount of money he will have after 42 years.
In total, he deposited:
$75*504months = $37,800
so he will have:
times the amount of money he deposited throughout this time.
Answer:
a) Discrete, because the number of point scored during basket ball is countable.
For instance, the amount of point scored in a basketball could be 75, 103, 63 etc. The numbers are countable
b) Continuous, because the amounts of rainfall is a random variable that is uncountable.
For instance, the amount of rainfall in City Upper B during April could be 0.10 inches of rain per hour, 0.30 inches of rain per hour. This numbers are not countable, they are rather approximated or rounded off.
Step-by-step explanation:
A random variable is considered discrete if its possible values are countable while a random variable is considered to be continuous if it's possible values are not countable.
PEMDAS: distribute the negative to (-2-5x) so it becomes (2+5x)+(-2)=18
Add 2 to both sides: 2+5x=20
Subtract 2: 5x=18
Divide 5: x= 18/5