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Dmitrij [34]
2 years ago
11

Evaluate (2-3)^(4) - 9 = 3. 0-7 0-2 0 1 02

Mathematics
2 answers:
hichkok12 [17]2 years ago
8 0

Answer:

Option (C) 1 is the correct answer.

Step-by-step explanation:

To solve the above equation we will follow the PEDMAS rule.

It stands for :

  • \purple\star Parentheses
  • \purple\star Exponents
  • \purple\star Multiplication
  • \purple\star Division
  • \purple\star Addition
  • \purple\star Subtraction

Evaluating the question by Pedmas rule :

\begin{gathered}\qquad{\twoheadrightarrow{\tt{(2 - 3) ^{4}(4) - 9 \div 3}}} \\  \\ \qquad{\twoheadrightarrow{\tt{( - 1) ^{4}(4) - 9 \div 3}}} \\  \\ \qquad{\twoheadrightarrow{\tt{(1) (4) - 9 \div 3}}} \\  \\ \qquad{\twoheadrightarrow{\tt{1 \times 4 - 9 \div 3}}} \\  \\ \qquad{\twoheadrightarrow{\tt{4 - 9 \div 3}}} \\  \\ \qquad{\twoheadrightarrow{\tt{4 - 3}}} \\  \\ \qquad{\twoheadrightarrow{\tt{1}}} \end{gathered}

Hence, the answer is 1.

\rule{300}{2.5}

EleoNora [17]2 years ago
6 0

Answer:

Step-by-step explanation:

(2-3)⁴ *4 - 9 + 3 = (-1)⁴ *4 - 9 + 3

                          = 1*4 - 9 +3

                          = 4 - 9 + 3

                          = - 5 + 3

                           = - 2

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The answer to this is 39°

Step-by-step explanation:

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4 years ago
In a sample of 1000 randomly selected consumers who had opportunities to send in a rebate claim form after purchasing a product,
Vadim26 [7]

Answer: 0.2872

Step-by-step explanation:

Given : In a sample of 1000 randomly selected consumers who had opportunities to send in a rebate claim form after purchasing a product, 260 of these people said they never did so.

i.e. n= 1000 and x= 260

⇒ Sample proportion : \hat{p}=\dfrac{260}{1000}=0.26

z-value for 95% confidence interval : z_c=1.960

Now, an upper confidence bound at the 95% confidence level for the true proportion of such consumers who never apply for a rebate. :-

\hat{p}+ z_c\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

=0.26+ (1.96)\sqrt{\dfrac{0.26(1-0.26)}{1000}}

=0.26+ (1.96)(0.01387)=0.26+0.0271852=0.2871852\approx0.2872

∴ An upper confidence bound at the 95% confidence level for the true proportion of such consumers who never apply for a rebate : 0.2872

7 0
3 years ago
QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu
Harman [31]

Answer:

(a)Revenue function, R(x)=580x-x^2

Marginal Revenue function, R'(x)=580-2x

(b)Fixed cost =900 .

Marginal Cost Function=300+50x

(c)Profit,P(x)=-35x^2+280x-900

(d)x=4

Step-by-step explanation:

<u>Part A </u>

Price Function= 580 - 10x

The revenue function

R(x)=x\cdot (580-10x)\\R(x)=580x-x^2

The marginal revenue function

\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x

<u>Part B </u>

<u>(Fixed Cost)</u>

The total cost function of the company is given by c=(30+5x)^2

We expand the expression

(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2

Therefore, the fixed cost is 900 .

<u> Marginal Cost Function</u>

If  c=900+300x+25x^2

Marginal Cost Function, \frac{dc}{dx}= (900+300x+25x^2)'=300+50x

<u>Part C </u>

<u>Profit Function </u>

Profit=Revenue -Total cost

580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900

<u> Part D </u>

To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

P(x)=-35x^2+280x-900\\P'(x)=-70x+280\\-70x+280=0\\-70x=-280\\$Divide both sides by -70\\x=4

The number of cakes that maximizes profit is 4.

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