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Elden [556K]
3 years ago
11

Describe how to determine if two lines are parallel, perpendicular or neither. Give an example of a parallel line, a perpendicul

ar line and a line which is neither parallel nor perpendicular to y=2/5x+7.
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
5 0

Answer:

In order to determine if two lines are parallel, perpendicular, or neither, look at their slopes. If the lines have the same slope, they are parallel. If the slopes are opposite reciprocals, then they are perpendicular. If the slopes of the lines are not any of those, then they are neither.

Parallel line: y = \frac{2}{5} x

Perpendicular line: y = -\frac{5}{2} x  

Neither: y = 3x

Step-by-step explanation:

In order to determine if two lines are parallel, perpendicular, or neither, look at their slopes. If the slopes of the two lines are the same, then they are parallel. If the slopes of the two lines are opposite reciprocals, then they are perpendicular. If the slopes of the lines are not any of those, then they are neither.  

The equation y = \frac{2}{5} x+7 is in slope-intercept form. The y is isolated and it's in y = mx + b format. Whenever an equation is in slope-intercept form, the m, or the coefficient of the x-term, represents the slope. So, the slope of the given line is \frac{2}{5}. Therefore, use the rules listed previously to find lines that are parallel and perpendicular.

Parallel lines have the same slope, so an example of a parallel line would be y = \frac{2}{5} x.

Lines that are perpendicular have slopes that are opposite reciprocals, so an example of a perpendicular line would be y = -\frac{5}{2} x.

Lines that are neither do not fall into either of those categories, so an example of a line that is neither would be  y = 3x.

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lubasha [3.4K]

The zeros of given function y=x^{2}+8 x+15 is – 5 and – 3

<u>Solution:</u>

\text { Given, equation is } y=x^{2}+8 x+15

We have to find the zeros of the function by rewriting the function in intercept form.

By using intercept form, we can put value of y as  to obtain zeros of function

We know that, intercept form of above equation is x^{2}+8 x+15=0

\text { Splitting } 8 x \text { as }(5+3) x \text { and } 15 \text { as } 5 \times 3

\begin{array}{l}{\rightarrow x^{2}+(5+3) x+5 \times 3=0} \\\\ {\rightarrow x^{2}+5 x+3 x+5 \times 3=0}\end{array}

Taking “x” as common from first two terms and “3” as common from last two terms

x (x + 5) + 3(x + 5) = 0

(x + 5)(x + 3) = 0

Equating to 0 we get,

x + 5 = 0 or x + 3 = 0

x = - 5 or – 3

Hence, the zeroes of the given function are – 5 and – 3

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Step-by-step explanation:

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Answer:

I’m pretty sure it’s Triangle ABC is congruent to Triangle DEF.

Step-by-step explanation:

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In triangle $ABC,$ point $D$ is on $\overline{AC}$ such that $AD = 3CD = 12$. If $\angle ABC = \angle BDA = 90^\circ$, then what
Neporo4naja [7]

Answer:

BD=4\sqrt{3}\ units

Step-by-step explanation:

we know that

AD=12\ units

3CD=12 ----> CD=4\ units

see the attached figure to better understand the problem

Triangles ABD and BCD are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional

so

\frac{BD}{AD}=\frac{CD}{BD}

substitute the given values

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BD=\sqrt{48}\ units

simplify

BD=4\sqrt{3}\ units

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3 years ago
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