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storchak [24]
3 years ago
7

Is 17 quarts greater than less than or equal to 4 gallons

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
6 0
17 quarts is greater than 4 gallons.

1 quart is equal to .25 gallons. So to find out how much 17 quarts equals in gallons, multiply the number of quarts by .25. You will figure out that 17 quarts is equal to 4.25 gallons which is greater than 4. So, 17 quarts is greater than 4 gallons.

Hope this helps! :)
Nadusha1986 [10]3 years ago
4 0
4 gallons = 16 quarts

17 quarts > 4 gallons

hope this helps 
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Answer:

8 years older then your younger sister

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Twenty-six students will attend the field trip to the career center. The cost to attend the career center is $x. Fifteen of thes
dexar [7]
Answer=I

15(x+3)+11x    represents the total cost

To solve for this, let's look at the information that we know...

26 students go on the trip

15 students pay $3 more for an additional class (x+3)

26-15=11

11students pay, x, the price of the trip.

So 15(x+3) represents the 15 students who pay for both the trip and the automotive class, and 11x represents the students who simply just pay for the cost of the trip.

Thus, 15(x+3)+11x represents the scenario
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3 years ago
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4 0
3 years ago
Two people share £350 in the ratio 1 : 6.<br><br><br>Calculate each share.
EleoNora [17]

Answer:

£50 and £300

Step-by-step explanation:

Sum the parts of the ratio 1 + 6 = 7 parts

Divide the amount by 7 to find the value of one part of the ratio

£350 ÷ 7 = £50 ← value of 1 part of ratio

Hence

1 person receives £50

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6 0
3 years ago
PLS PLS HELP, I DONT WANT TO FAIL!!
Flura [38]

Answer:

2.0 seconds

Step-by-step explanation:

<u>Given quadratic functions</u>:

\begin{cases}y=-7x^2+26x+3\\y=-6x^2 +23x+5\end{cases}

To find the time, in seconds, that the balloons collided at the highest point, <u>substitute</u> one equation into the other equation and rearrange to <u>equal zero</u>:

\begin{aligned}-6x^2+23x+5 & = -7x^2+26x+3\\-6x^2+23x+5+7x^2 & = -7x^2+26x+3+7x^2\\x^2+23x+5 & = 26x+3\\x^2+23x+5-26x & = 26x+3-26x\\x^2-3x+5& = 3\\x^2-3x+5-3& = 3-3\\x^2-3x+2& = 0\end{aligned}

<u>Factor</u> the quadratic:

\begin{aligned}x^2-3x+2 & = 0\\x^2-2x-x+2 & = 0\\x(x-2)-1(x-2) & = 0\\(x-1)(x-2) & = 0\\\end{aligned}

Apply the <u>zero-product property</u> to solve for x:

\implies (x-1)=0 \implies x=1

\implies (x-2)=0 \implies x=2

Therefore, the balloons collided at 1 second and 2 seconds.  

To find at which time the highest point of collision occured, substitute both values of x into one of the functions:

f(1)=-6(1)^2 +23(1)+5=22

f(2)=-6(2)^2 +23(2)+5=27

Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.

Learn more about quadratic systems of equations here:

brainly.com/question/27930827

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1 year ago
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