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AlekseyPX
3 years ago
14

In what periods are the lanthanides and actinides? Where are they

Mathematics
1 answer:
aksik [14]3 years ago
6 0

Lanthanides are in period 6 and actinides are in period 7. They are at the down part of the page so that the periodic table can fit on the page.

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Write (3a)^3 without exponents
makkiz [27]

Answer: 27a^3

It is 27a^3 because if you do 3×3=9 then 9×3= 27

7 0
3 years ago
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Consider that ΔDEF is similar to ΔGHI and the measure of ∠E is 58°. What is the measure of ∠H?
spayn [35]

Answer:

58 degrees

Step-by-step explanation:

If figures are similar to each other, it means that they have the same measures. Therefore, D has the same measure as G, E has the same measure as H, and F has the same measure as I.

6 0
3 years ago
What the y-intercept of (8,0) and (3,7)
Anettt [7]

Answer:

\sf \bf y - intercept = \dfrac{56}{5}

Step-by-step explanation:

Y-intercept:

   (8,0)  ; x₁ = 8 & y₁ = 0

   (3,7)   ; x₂= 3  & y₂ = 7

  • First find the slope of the line.

      \sf \boxed{\bf Slope =\dfrac{y_2-y_1}{x_2-x_1}}

                  \sf = \dfrac{7 - 0}{3 - 8}\\\\ =\dfrac{7}{-5}\\\\=\dfrac{-7}{5}

 slope y-intercept form of the line:  y = mx + b

Substitute the slope and x and y in the above equation. We can choose anyone of the given points.

     0 = \dfrac{-7}{5}*8 + b\\\\0=\dfrac{-56}{5}+b\\\\\dfrac{56}{5}=b\\\\ \boxed{\bf b = \dfrac{56}{5}}

3 0
2 years ago
What is the scale factor from figure A to figure B?
Andrej [43]

Answer:

hi its simple.

Step-by-step explanation:

9;3

or simplified...

3;1

3 0
3 years ago
Read 2 more answers
5. If position of object x = 3 sinΘ – 7 cosΘ then motion of object is bounded between position.​
lesya692 [45]

9514 1404 393

Answer:

  ±√58 ≈ ±7.616

Step-by-step explanation:

The linear combination of sine and cosine functions will have an amplitude that is the root of the sum of the squares of the individual amplitudes.

  |x| = √(3² +7²) = √58

The motion is bounded between positions ±√58.

_____

Here's a way to get to the relation used above.

The sine of the sum of angles is given by ...

  sin(θ+c) = sin(θ)cos(c) +cos(θ)sin(c)

If this is multiplied by some amplitude A, then we have ...

  A·sin(θ+c) = A·sin(θ)cos(c) +A·cos(θ)sin(c)

Comparing this to the given expression, we find ...

  A·cos(c) = 3   and   A·sin(c) = -7

We know that sin²+cos² = 1, so the sum of the squares of these values is ...

  (A·cos(c))² +(A·sin(c))² = A²(cos(c)² +sin(c)²) = A²(1) = A²

That is, A² = (3)² +(-7)² = 9+49 = 58. This tells us the position function can be written as ...

  x = A·sin(θ +c) . . . . for some angle c

  x = (√58)sin(θ +c)

This has the bounds ±√58.

3 0
3 years ago
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