<u>Answer:</u> The temperature when the volume and pressure has changed is -27.26°C
<u>Explanation:</u>
To calculate the temperature when pressure and volume has changed, we use the equation given by combined gas law. The equation follows:

where,
are the initial pressure, volume and temperature of the gas
are the final pressure, volume and temperature of the gas
We are given:
![P_1=725mmHg\\V_1=12L\\T_1=30.00^oC=[30+273]K=303K\\P_2=252mmHg\\V_2=28L\\T_2=?K](https://tex.z-dn.net/?f=P_1%3D725mmHg%5C%5CV_1%3D12L%5C%5CT_1%3D30.00%5EoC%3D%5B30%2B273%5DK%3D303K%5C%5CP_2%3D252mmHg%5C%5CV_2%3D28L%5C%5CT_2%3D%3FK)
Putting values in above equation, we get:

Converting this into degree Celsius, we get:


Hence, the temperature when the volume and pressure has changed is -27.26°C
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Answer:
1. more slowly than
2. larger than
3. weaker
Explanation:
Acetone molecules are bonded by very weak intermolecular forces when compared to that of the hydrogen bond between water molecules. This makes it very easy for acetone molecules to vaporize easily into its gaseous state, much more faster than water molecules (since the acetone molecules need a lesser amount of energy to break these bonds). Also, the boiling point of liquid acetone is much lower than that of water, meaning that it has a higher vapor pressure than that of water.
<span>A 1 molar solution is the molecular weight in grams in 1 litre of water, so a 3.5 molar solution would be 58.44g multiplied by 3.5, which is 204.54g in 1L.</span>
Answer:
Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation
Explanation:
Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation Assignment: 06.05 Data Observation