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sergeinik [125]
3 years ago
13

6. The oxidizing agent for the following reaction below is..Al + Mn07 - Al(OH)2 + MnO2​

Chemistry
1 answer:
prisoha [69]3 years ago
4 0
Think of the acronym LEO says GER: losing electrons is oxidation, gaining electrons is reduction.
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Calculate the ionization constant for the following acids or bases from the ionization constant of its conjugate base or conjuga
suter [353]

Answer:

7.41 × 10⁻⁵

Explanation:

Let's consider the basic dissociation reaction of trimethylamine (CH₃)N).

(CH₃)N + H₂O = (CH₃)NH⁺ + OH⁻

According to Brönsted-Lowry, in this reaction (CH₃)N is a base and (CH₃)NH⁺ is its conjugate acid. The pKb for (CH₃)N is 9.87. We can calculate the pKa of (CH₃)NH⁺ using the following expression.

pKa + pKb = 14

pKa = 14 - pKb = 14 - 9.87 = 4.13

Then, we can calculate the acid dissociation constant for (CH₃)NH⁺ using the following expression.

pKa = -log Ka

Ka = antilog - pKa = antilog -4.13 = 7.41 × 10⁻⁵

8 0
3 years ago
How many grams are in 2.34 mol Co?
fgiga [73]

Hi! To find the amount of grams in 2.34 moles of cobalt, you must use the following equation:

2.34 mol Co * (58.93 g Co)/(1 mol Co)

The answer would therefore be 137.9 grams

6 0
4 years ago
(a) starting with solid sucrose, c12h22o11, describe how you would prepare 250 ml of a 0.250 m sucrose solution. (b) de- scribe
Anna007 [38]

a. We first calculate the moles of sucrose needed

moles sucrose = 0.250 M * 0.25 L

moles sucrose = 0.0625 mol

 

The molar mass of sucrose 342.3 g/mol, so the mass of sucrose needed is:

mass sucrose = 0.0625 mol * 342.3 g/mol

mass sucrose = 21.4 grams

 

So simply dissolved about 21.4 grams of sucrose in 250 mL solution.

 

b. We use the formula:

M1 V1 = M2 V2

1.50 M * V1 = 0.100 M * 0.350 L

V1 = 0.0233 L = 23.3 mL

 

So simply take 23.3 mL of solution from 1.50 M then dilute it with water until 350 mL to make 0.100 M.

5 0
4 years ago
How many liters would you need to make a 1 m solution if you have 6 mil of sodium hydroxide
Andru [333]

Answer:

molarity = no. of moles of solute / 1 liter .

* one moles of sodium hydroxide = 40 gm of sodium hydroxide.

so we can said ; if want prepare 1 molar NaOH solution then we need 40 gm NaOH dissolve in one liter of water so it became one 1 molar NaOH solution

Explanation:

5 0
3 years ago
A scientist and his friend walked into a bar. The Scientist said: "May I please get some H2O". the waitress asked his friend wha
Aleksandr [31]

Answer:

The waitress thought the man meant H202 which is Hydrogen Peroxide. The man drank the Hydrogen Peroxide and then died.

5 0
3 years ago
Read 2 more answers
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