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4 years ago

Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?

Chemistry

2 answers:

Romashka-Z-Leto [24]4 years ago

7 0

Answer: The correct answer is Option 2.

Explanation:

When carbon burns in the presence of oxygen, it produces a gas known as carbon dioxide.

To write a chemical equation, we must follow some of the rules:

The reactants are written on the left side of the direction arrow.
A '+' sign is written between the reactants, if more than one reactant is present.
An arrow is added after all the reactants are written.
The products are written on the right side of the direction arrow.
A '+' sign is written between the products, if more than one reactant is present.

Here, carbon and oxygen are the reactants and carbon dioxide is the product.

Thus, the chemical equation representing this reaction follows:

$\text{Carbon}+\text{Oxygen}\rightarrow \text{Carbon dioxide}$

Hence, the correct answer is Option 2.

sasho [114]4 years ago

6 0

2.) carbon + oxygen → carbon dioxide

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If the reaction 2HgO --> 2Hg + O2 is endothermic, which bonds are the strongest?

Alika [10]

Endothermic reaction means the reactant side takes heat from surrounding and get decomposed i.e ∆H=-ve
If the equation is exothermic then it means the reactant is happy to decompose .But it's not as it's endothermic

Now

HgO is Omitted from our solution option.

Hg is a atom so no bonds hence no bond strength occurs.

O_2 is a molecule and so it's our answer .

3 0

2 years ago

In pure water at 25 °C, the concentration of a saturated solution of CuF2 is 7.4 × 10−3 M. If measured at the same temperature,

Romashka-Z-Leto [24]

Answer:

The concentration of a saturated solution of CuF₂ in aqueous 0.20 M NaF is 4.0×10⁻⁵ M.

Explanation:

Consider the ICE take for the solubility of the solid, CuF₂ as:

CuF₂ ⇄ Cu²⁺ + 2F⁻

At t=0 x - -

At t =equilibrium (x-s) s 2s

The expression for Solubility product for CuF₂ is:

$K_{sp}=\left [ Cu^{2+} \right ]\left [ F^- \right ]^2$

$K_{sp}=s\times {2s}^2$

$K_{sp}=4s^3$

Given s = 7.4×10⁻³ M

So, Ksp is:

$K_{sp}=4\times (7.4\times 10^{-3})^3$

Ksp = 1.6209×10⁻⁶

Now, we have to calculate the solubility of CuF₂ in NaF.

Thus, NaF already contain 0.20 M F⁻ ions

Consider the ICE take for the solubility of the solid, CuF₂ in NaFas:

CuF₂ ⇄ Cu²⁺ + 2F⁻

At t=0 x - 0.20

At t =equilibrium (x-s') s' 0.20+2s'

The expression for Solubility product for CuF₂ is:

$K_{sp}=\left [ Cu^{2+} \right ]\left [ F^- \right ]^2$

$1.6209\times 10^{-6}={s}'\times ({0.20+2{s}'})^2$

Solving for s', we get

s' = 4.0×10⁻⁵ M

The concentration of a saturated solution of CuF₂ in aqueous 0.20 M NaF is 4.0×10⁻⁵ M.

3 0

4 years ago

If 11.7 g of aluminum reacts with 37.2 g of copper (II) sulfate according to the following reaction, how many grams of aluminum

zhannawk [14.2K]

Answer:

There is 26.59 grams of aluminium sulfate produced

Explanation:

Step 1: Data given

Mass of aluminium = 11.7 grams

Mass of copper (II) sulfate = 37.2 grams

Molar mass of Aluminium = 26.98 g/mol

Molar mass of CuSO4 = 159.61 g/mol

Molar mass of Al2(SO4)3 = 342.15 g/mol

Step 2: The balanced equation

2Al + 3CuSO4 → Al2(SO4)3 + 3Cu

Step 3: Calculate moles of Aluminium

Moles Al = mass Al / molar mass Al

Moles Al = 11.7 grams / 26.98 g/mol

Moles Al = 0.434 mol

Step 4: Calculate moles of CuSO4

Moles CuSO4 = 37.2 grams / 159.61 g/mol

Moles CuSO4 = 0.233 moles

Step 5: Calculate limiting reactant

For 2 moles of Al we need 3 moles of CuSO4

CuSO4 is the limiting reactant. It will be completely consumed (0.233 moles).

Al is in excess. There will be consumed 0.233 *(2/3) = 0.1553 moles

There will remain 0.434 - 0.1553 = 0.2787 moles

Step 6: Calculate moles of Al2(SO4)3

For 2 moles of Al we need 3 moles of CuSO4, to produce 1 mole of Al2(SO4)3 and 3 moles of Cu

For 0.233 moles CuSO4 we produce 0.233/3 = 0.0777 moles of Al2(SO4)3

Step 7: Calculate mass of Al2(SO4)3

Mass of Al2(SO4)3 = moles Al2(SO4)3 * molar mass Al2(SO4)3

Mass of Al2(SO4)3 = 0.0777 moles * 342.15g/mol

Mass of Al2(SO4)3 = 26.59 grams

There is 26.59 grams of aluminium sulfate produced

4 0

3 years ago

a television remote control operates at 319 THz, what is the wavelength of the infrared light in nanometers?

AURORKA [14]

Given:

Frequency (ν) = 319 THz

To determine:

The wavelength corresponding to the given frequency

Explanation:

Wavelength (λ) and Frequency(ν) are related as:

λ = c/ν

where c = speed of light = 3*10⁸ m/s

Now:

SI unit of frequency is Hertz (Hz) also expressed as cycles per second

i.e 1 Hz = 1 s⁻¹

1 Terahertz (THz) = 10¹² Hz

therefore the given frequency ν = 319 *10¹² s⁻¹

λ = 3 * 10⁸ ms⁻¹/319 *10¹² s⁻¹ = 940 * 10⁻⁹ m

since 1 nanometer (nm) = 10⁻⁹ m

The wavelength is λ = 940 nm

Ans: The infrared wavelength = 940 nm

7 0

4 years ago

What is the sum of vectors

yuradex [85]

The sum of vectors is the value given when two or more vectors are added together, in what is known as a vector addition.

Hopefully, this helps.

4 0

3 years ago