Answer:
18
Explanation:
Sabemos que la fórmula química del agua es H2O.
Usando la información que; H = 1, O = 16, podemos calcular la masa molar del agua de la siguiente manera
[2 (1) + 16] = 18
Por tanto, la masa molar del agua es 18
NaBr < H3O+1 = OH-1 < Na^+1 = Br^-1 < H2O
<span>Least is NaBr (100% dissolved so no NaBr remains, only Na^+1 and Br^-1 </span>
<span>H2O yields 10^-7 M H3O^+1 and 10^-7 M OH^-1 (Kw = 1x10^-14 = [H3O+][OH-] </span>
<span>Na^+1 and Br^-1 will bothe be 0.1 M </span>
<span>H2O is slightly less that 1000 g / L in a 0.1 M NaBr solution, so its concentration is about 55.5 M</span>
Gas particles lose their energy during collisions
The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.
<h3>What is Enthalpy of Fusion ?</h3>
The amount of energy needed to change 1 mole of substance under state change at constant temperature and pressure is called enthalpy of fusion. It is also known as Latent heat of fusion. Unit of enthalpy of fusion is kJ/mol.
<h3>How to find the change in energy ? </h3>
To find the change in energy use this expression:
q = n ΔH
where
q = Energy change
n = number of moles
ΔH = Molar enthalpy
Number of moles (n) =
=
= 0.39 mol
Now put the values in above formula we get
q = n ΔH
= 0.39 mol × 2.29 kJ/mol
= 0.89 kJ
Thus from the above conclusion we can say that The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.
Learn more about the Latent heat of fusion here: brainly.com/question/87248
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