56 ounces are 3.5 pounds because 16 ounces are 1 pound and if you divide 56 by 16 you get 3.5
Absolute value is just how many integers rhat number is away from 0. i say this because it’s not too hard of a thing to learn and it’s very important in the higher grades.
3 is 2 6/7
5 is a greater than symbol >
7 is 1/3 and negative 1/3 so -1/3
8 is 14 and -14
9 is 21 and -21
11 is | -75 |
i’m not sure about 13 but i believe it could be | -8 |
i hope this helped
Answer:
(3,-4) or x=3 and y= -4
Step-by-step explanation:
I'm going to solve this by substitution
We first need to get a variable by itself in one of the two equations (it doesn't matter which variable and the equation you do the work on doesn't matter either)
I'm going to solve for y in the second equation
-4x-4y=4
add 4y and subtract 4 from both sides to get
-4x-4=4y
Divide by 4 to get
-x-1=y
We can plug this value in for y into the first equation and get
4x+5(-x-1)= -8
Solve for x
4x-5x-5= -8
-x-5= -8
-x= -3
x=3
We can plug this value into one of the first two equations and solve for y
4(3)+5y= -8
12+5y= -8
5y= -20
y= -4
Therefore the solution is (3,-4) or x=3 and y= -4
Answer:
C.
Step-by-step explanation:
The bottom-right most cell tells us that the total number of students that responded to the survey is 310 students.
To find the answer, we can go through each choice.
A. Females taking Geometry
Row 1 Column 2 tells us that 53 females are taking geometry. 53/310 is about 17%.
B. Females taking Algebra II.
Row 1 Colume 3 tells us that 62 females are taking Algebra II. 62/310 is 20%.
C. Males taking Geometry.
Row 2 Colume 2 tells us that 59 males are taking Geometry. 59/310 is about 19%. Choice C is correct.
D. Males taking Algebra I.
44 out of the total 310 respondents are male and is taking Algebra I. 44/310 is about 14%.
Given,
3/3x + 1/(x + 4) = 10/7x
1/x + 1/(x+4) = 10/7x
Because the first term on LHS has 'x' in the denominator and the second term in the LHS has '(x + 4)' in the denominator. So to get a common denominator, multiply and divide the first term with '(x + 4)' and the second term with 'x' as shown below
{(1/x)(x + 4)/(x + 4)} + {(1/(x + 4))(x/x)} = 10/7x
{(1(x + 4))/(x(x + 4))} + {(1x)/(x(x + 4))} = 10/7x
Now the common denominator for both terms is (x(x + 4)); so combining the numerators, we get,
{1(x + 4) + 1x} / {x(x + 4)} = 10/7x
(x + 4 + 1x) / (x(x + 4)) = 10/7x
(2x + 4) / (x(x + 4)) = 10/7x
In order to have the same denominator for both LHS and RHS, multiply and divide the LHS by '7' and the RHS by '(x + 4)'
{(2x+4) / (x(x + 4))} (7 / 7) = (10 / 7x) {(x + 4) / (x + 4)}
(14x + 28) / (7x(x + 4)) = (10x + 40) / (7x(x + 4))
Now both LHS and RHS have the same denominator. These can be cancelled.
∴14x + 28 = 10x + 40
14x - 10x = 40 - 28
4x = 12
x = 12/4
∴x = 3
