Answer:
102
Step-by-step explanation:
We have the mean (m) 128.5 and the standard deviation (sd) 8.2, we must calculate the value of z for each one and determine whether or not it is an outlier:
z = (x - m) / sd
In the first case x = 148:
z = (148 - 128.5) /8.2
z = 2.37
In the second case x = 102:
z = (102 - 128.5) /8.2
z = -3.23
In the first case x = 152:
z = (152 - 128.5) /8.2
z = 2.86
The value of this is usually between -3 and 3, therefore when x is 102 it goes outside the range of the value of z, which means that this is the outlier.
Answer:
What are the coordinates of the resulting figure?
✔ (0, 0), (4, 0), (4, –4), (0, –2)
Step-by-step explanation:
its C on Edge
I just took this assignment and got it right
The solutions to the questions are given below
a)
sample(n) word length sample mean
1 5,4,4,2 3.75
2 3,2,3,6 3.5
3 5,6,3,3 4.25
b)R =0.75
c)
- The mean of the sample means will tend to be a better estimate than a single sample mean.
- The closer the range of the sample means is to 0, the more confident they can be in their estimate.
<h3>What is the students are going to use the sample means to estimate the mean word length in the book.?</h3>
The table below shows sample means in the table.
sample(n) word length sample mean
1 5,4,4,2 3.75
2 3,2,3,6 3.5
3 5,6,3,3 4.25
b)
Generally, the equation for is mathematically given as
variation in the sample means
R =maximum -minimum
R=4.25-3.5
R =0.75
c)
In conclusion, In most cases, the mean of many samples will provide a more accurate estimate than the mean of a single sample.
They may have a higher level of confidence in their estimate if the range of the sample means is closer to 0 than it is now.
Read more about probability
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Subtracting 3x^4+9x^3+3x^2 from the divided and bringing down 13x.
it is given in the question that
Alpha printing will make 400 brochures for $100. Omega printing will make 1,000 brochures for $100.
For Alpha, cost of 1 brochure is

For Omega,
Cost of 1 brochure is

So choosing Omega printing, you will save

on each brochure .