We have the following equation:
3x2 + 7x + 4 = 0
Using the resolver we have:
x = (- b +/- root (b2 - 4ac)) / 2a
Substituting values we have:
x = (- (7) +/- root ((7) 2 - 4 (3) (4))) / 2 (3)
Rewriting:
x = (- 7 +/- root (49 - 48)) / 6
x = (- 7 +/- root (1)) / 6
x = (- 7 +/- 1) / 6
The results are:
x = (- 7 + 1) / 6 = -6/6 = -1
x = (- 7 - 1) / 6 = -8 / 6 = -4/3
Answer:
x = -1
x = -4/3
option C and D
If a² + b² = c², then the triangle is <u>right</u>.
So we have (8)² + (11)² <u>?</u> (13)²
(8)² is 64, (11)² is 121, and (13)² is 169.
So we have 64 + 121 <u>?</u> 169
64 + 121 is 185 and we can see that 185 > 169.
This triangle would not be a right triangle.
In fact, it would be an acute triangle.
So no, it's not a right triangle.
Answer: n=-7
Step-by-step explanation:
3n-7=6n-2n
3n-7=4n
-7=n
n=-7
Answer:
71.70
Step-by-step explanation:
