Not likely because in my class we have more boys then girls
m=27
f=5
Answer:
x=0, - 9
Step-by-step explanation:
x^2+9x=0
x(x+9)=0
x=0 or x=-9
If a,b,c are the 3 positive integers
1/a +1/b +1/c > 6/abc
(bc+ac+ab)/abc >6/abc so
(bc+ac+ab)>6
The lowest positive integers that are different are 1,2,3 so the lowest value that (bc+ac+ab) could have is 1•2+2•3+1•3=2+6+3= 11 therefore
1/a +1/b +1/c > 6/abc is true
