Answer:
15
Step-by-step explanation:
Rate of change or slope or gradient of a line passes two points (x1, y1) and (x2, y2) could be calculated by:
(y2 - y1)/(x2 - x1)
=> Rate of change of the line passing (1,15) and (3,45):
(45 - 15)/(3 - 1) = 30/2 = 15
Answer:
f(x) = - 4x² + 24x - 20
Step-by-step explanation:
Given
f(x) = - 4(x - 3)² + 16 ← expand the factor using FOIL
= - 4(x² - 6x + 9) + 16 ← distribute parenthesis by - 4
= - 4x² + 24x - 36 + 16 ← collect like terms
= - 4x² + 24x - 20
Answer:
The answer is given below
Step-by-step explanation:
The loads in the circuit are continuous duty, so the circuit can only loaded to 80% of its current rating.
Calculate 80% current rating of the circuit breaker.
Icb = [ 80/100] (20 A)
= (O.8) (20 A )
= 16 A
Now we assume that the value of supply voltage is 120 V
Now we will calculate current flows via under water light which will be taken as Load 1
<em>Ii = </em>500 W/120 V
= 4.167 A
Current via the circulating pump which will be taken as Load 2 IS 8.5 A
<em>I = </em>load1 + load 2
<em> = 4.167 A + 8.5 A</em>
<em> = 12.67 A</em>
The total current in the circuit obtained which is less than the circuit breaker rating current. Therefore, the power can be operated for both the loads.
Answer:
Train A is faster by a factor of 1.01
Step-by-step explanation:
Given:
Train A:
Distance = 175 Miles
Time = 4 Hours
Train B:
y=43.5x
To Find:
which train travels at a faster rate in by what factor =?
Solution:
The speed of the train A = 
The speed of train A =
The speed of train A = 43.75 miles per hour
Speed of the train B is the slope of the given line
The standard equation of the slope of the line is
y = mx+b
where m is the slope
and we are given with
y = 43.5x
So comparing with the standard equation
m = 43.5
Hence the speed of train B is 43.5 miles per hours
Train A travels faster
rate =1.01
