Number one is x=9,-9
number two is x=0
number three is x=12,-12
number four is 5i, -5i
Answer:
The y could be 9 and the b could be 9 so it would be 9+9 = 18
Step-by-step explanation:
9+9 = 18
Hope this helps.
Answer:
10/10
Tama po Yan Yan po isagot nyo
Answer: C
<u>Step-by-step explanation:</u>
∑ 8(
)⁽ⁿ⁻¹⁾ from n = 1 to n = 5
n = 1 → 8(
)⁽¹⁻¹⁾
= 8 = ![\frac{648}{81}](https://tex.z-dn.net/?f=%5Cfrac%7B648%7D%7B81%7D)
n = 2 → 8(
)⁽²⁻¹⁾
=
=
n = 3 → 8(
)⁽³⁻¹⁾
=
= ![\frac{3528}{81}](https://tex.z-dn.net/?f=%5Cfrac%7B3528%7D%7B81%7D)
n = 4 → 8(
)⁽⁴⁻¹⁾
=
= ![\frac{8232}{81}](https://tex.z-dn.net/?f=%5Cfrac%7B8232%7D%7B81%7D)
n = 5 → 8(
)⁽⁵⁻¹⁾
=
= ![\frac{19208}{81}](https://tex.z-dn.net/?f=%5Cfrac%7B19208%7D%7B81%7D)
Sum = ![\frac{33128}{81}](https://tex.z-dn.net/?f=%5Cfrac%7B33128%7D%7B81%7D)
= 408.99
Answer:
5.3×10⁻¹¹ m
Step-by-step explanation:
Applying,
v = 2πr/t................ Equation 1
Where v = speed of the electron in the orbit, r = radius of the orbit, t = time, π = pie
make r the subject of the equation
r = vt/2π................ Equation 2
From the question,
Given: v = 2.2×10⁶ m/s, t = 1.5×10⁻¹⁶ s
Constant: π = 3.14
Susbtitute these values into equation 2
r = (2.2×10⁶×1.5×10⁻¹⁶)/(3.14×2)
r = (3.3×10⁻¹⁰)/6.28
r = 5.3×10⁻¹¹ m
Hence the radius of the orbit is 5.3×10⁻¹¹ m