Question

Solve for x 12x+7 < -11 OR 5x-8 > 40

Answer 1

12x+7 < -11:
Subtract 7 from each side.
12x+7 < -11
      -7     -7
12x < -18
Divide each side by 12.
12x < -18
-----    -----
12       12
x < -1.5 or x < -3/2
5x-8 > 40:
Add 8 to each side.
5x-8 > 40
   +8    +8
5x > 48
Divide each side by 5.
5x > 48
----   ----
 5      5
x > 9.6
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Answer 2

Answer:

The solution is x<- 3/2 or x 48/5.

Step-by-step explanation: this is for the khan academy peeps :)